Consider the analog signal xa(t) = 12*sin(240* pi*t) volts.5) Ifthe sampling rate is Fs=540HZ and using 2048 quantization levels, determine the following:a) Dynamic Range (DR)b) Resolution (A)c) Output bit rate of the ADCd) Over-allfile size in bytes if one (1) minute of the analog signal (audio tone) is processed.e) The quantization error at the n=100 samplef) The quantization error at the n=200 sample

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Answered: Consider the analog signal xa(t) =…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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1as soon as possible , please
a) In an audio system music signal is band limited to 5kHz.It is digitized so that the peak signal power to quantization noise power is at least 104dB. Calculate: i) The sampling rate if the signal is sampled at a rate 3.5 times the Nyquist rate; b) c) ii) The number of quantization levels; iii) Number of bits per sample. iv) Bit rate; and
This multiple choice question from DIGITAL COMMUNICATIONS course.just write for me the final answer. 11)The output signal-to-noise ratio of a uniform quantizer, for a full load test tone, is equal to 61.8 dB. The number of bits per sample is a)none of the mentioned b)9 c)8 d)10
An analog signal is to be coded by an ADC. The signal contains significant frequencies up to 3.2kHz. If the system is operated at a bit rate of 36,000 bits per second (bps), answer the following: a) To avoid aliasing, the sampling frequency must be greater than or equal to kHz b) If the signal is sampled at the Nyquist rate, what is the Nyquist frequency? kHz h c) If the signal is sampled at the Nyquist rate, the number of bits per sample is number of quantization levels is and the Note: *When you use the formula bFs L in finding b, the result must be rounded up to the nearest integer.
Consider error control methods in digital signal transmission. Assume Hamming code is used with even parity. (a) Assume the received code word is 1110101001, determine if the code word is correct. If no, identify the wrong bit and obtain the original data word. (b) If the analogue signal before digitalisation is of frequency from 200 Hz to 1.5k Hz. What is the lowest sampling frequency? (c) Following (a) (b), determine the bandwidth requirement for transmitting the digital message.
In sampling a 3.4 KHz telephone quality voice signal using 10 bits, the average number of steps taken by the ramp method of analog to digital conversion is:
A signal is sampled by using sampling frequency of 70000HZ which will produce 8500 Hz separation between repetitive spectrum copies then the frequency of the signal assuming that sampling frequency is doubled is. Hz
2. A singer voice is sampled for 4 second by an 8-bit ADC at a sampling frequency of 10 kHz. The samples are stored on a memory chip. What is the minimum memory size both in [bits and bytes] required to store all the samples? ii. How long the signal must be sampled to store the samples in 100Mbytes CD- ROM iii. What should be the highest frequency component of the signal? iv.If sampling frequency is doubled then how long the signal must be sampled to store samples in 100Mbytes CD-ROM
b. Maximum frequency of an analog video signal is 5 MHz. If this analog video signal is sent in digital form at the data rate of 100 Mbps, what is the number of required quantization levels?
Write program to enter and draw, as a DT signal, the following two sequences: A-[3, 6, 9, 12] and B- [10, 20, 30]. The two figures should be displayed in one window vertically (A on top, and B down). (MATLAB/OCTAVE software)
10101010000 Binary frequency shift keying (FSK) is adopted as the modulation technique. The FSK modulator specification is as follows: Bit Rate: 20000 bit/sec Carrier Signal: 50 sin (2n 60000t) Frequency shift, Af= 20000 Hz i) Determine mark and space frequency for this system. ii) Sketch the output for the digital signal.
Wire size and voltage drop The cross-sectional area of wire is measured in circular mils (CM). 1 mil = 1/1000 inch CM = squaring of mil Example 1: Find CM for a piece of wire has a diameter of .008 of an inch. .008 = 8/1000 = 8 mils CM = 8² = 64 Find CM for a piece of wire has a diameter of .008 of an inch. 5. Find Cm for a piece of wire has a diameter of .064 of an inch. 6. Find CM for a Wire has 24 strands of wire and each strand is .012 inches in diameter.

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