Consider the a force vector of 25.0 Newtons, applied at an angle of 60.0 degrees south of west. Determine the horizontal and vertical components of this vector. 60⁰ 7 OFx12.5 N west, O Fx = 25.0 west, O Fx = 21.6 N west, O Fx = 10.0 N west, Fy = 21.6 N south Fy=25.0 south Fy=12.5 N south Fy=15.0 N south
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