Consider taking a 5 kg block of ice at -80 °C, and heating up until you have that same 5 kg of water as steam at 200 °C. You can divide this process into 5 steps. Which one of these required the most amount of energy? Here are some relevant data values. Cs(ice) = 2030 J/kg K Cs(water) = 4184 J/kg K Cs(steam) = 2080 J/kg K AfusionH = 333 kJ/kg Avapourization H = 2257 kJ/kg Heating ice from -80 °C to its melting point. Melting the ice. Heating water to its boiling point. Boiling the water to form steam. Heating the steam to 200 °C.

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Consider taking a 5 kg block of ice at -80 °C, and heating up until you have that same
5 kg of water as steam at 200 °C. You can divide this process into 5 steps. Which one
of these required the most amount of energy?
Here are some relevant data values.
Cs(ice) = 2030 J/kg K
Cs(water) = 4184 J/kg K
Cs(steam) = 2080 J/kg K
AfusionH = 333 kJ/kg
Avapourization H = 2257 kJ/kg
Heating ice from -80 °C to its melting point.
Melting the ice.
Heating water to its boiling point.
Boiling the water to form steam.
Heating the steam to 200 °C.
Transcribed Image Text:Consider taking a 5 kg block of ice at -80 °C, and heating up until you have that same 5 kg of water as steam at 200 °C. You can divide this process into 5 steps. Which one of these required the most amount of energy? Here are some relevant data values. Cs(ice) = 2030 J/kg K Cs(water) = 4184 J/kg K Cs(steam) = 2080 J/kg K AfusionH = 333 kJ/kg Avapourization H = 2257 kJ/kg Heating ice from -80 °C to its melting point. Melting the ice. Heating water to its boiling point. Boiling the water to form steam. Heating the steam to 200 °C.
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