Consider R= 30 Q for the circuit given below. lic t = 0 R 3u(-t) A (1) 2.5 µF vc iR VL. 20 mH Dotormino idot +

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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**Problem Statement:**

Consider \( R = 30 \, \Omega \) for the circuit given below.

**Circuit Diagram Details:**

1. **Current Source:** Provides \( 3u(-t) \, \text{A} \).
2. **Capacitor:** 
   - Capacitance: \( 2.5 \, \mu \text{F} \).
   - Voltage across capacitor: \( v_C \).
   - Current through capacitor: \( i_C \).

3. **Resistor 1:** 
   - Resistance: \( 2 \, \Omega \).

4. **Inductor:** 
   - Inductance: \( 20 \, \text{mH} \).
   - Voltage across inductor: \( v_L \).
   - Current through inductor: \( i_L \).

5. **Switch:** 
   - Open at \( t = 0 \).

6. **Resistor 2:** 
   - Resistance: \( R \).
   - Current through resistor: \( i_R \).

**Task:**

Determine \( i_C(0^+) \).

**Solution Format:**

The value of \( i_C(0^+) \) is \_\_\_\_ A. (Round the final answer to three decimal places.)
Transcribed Image Text:**Problem Statement:** Consider \( R = 30 \, \Omega \) for the circuit given below. **Circuit Diagram Details:** 1. **Current Source:** Provides \( 3u(-t) \, \text{A} \). 2. **Capacitor:** - Capacitance: \( 2.5 \, \mu \text{F} \). - Voltage across capacitor: \( v_C \). - Current through capacitor: \( i_C \). 3. **Resistor 1:** - Resistance: \( 2 \, \Omega \). 4. **Inductor:** - Inductance: \( 20 \, \text{mH} \). - Voltage across inductor: \( v_L \). - Current through inductor: \( i_L \). 5. **Switch:** - Open at \( t = 0 \). 6. **Resistor 2:** - Resistance: \( R \). - Current through resistor: \( i_R \). **Task:** Determine \( i_C(0^+) \). **Solution Format:** The value of \( i_C(0^+) \) is \_\_\_\_ A. (Round the final answer to three decimal places.)
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