The correct answer is A but why can’t it be B , also I can’t seem to understand the correct way to do it Consider points A = (1,0,1) and B=(0, 1, 0)and riface{ x+y=1(z=y+land lines S:a) There exists C Er, such that A, B, C are collinearb) For all points CES, A, B, C are collinear2) For all points CEr, the triangle of vertices A, B, C are equal to 1.

By finding the equation of line passing through A and B, we can solve the question.

Consider points A=(1,0,1) and B=(0,1,0) fasa and r [x+y=1 (==y+l and lines S: a) There exists C Er, such that A, B, C are collinear b) For all points CES, A,B,C are collinear 2) For all points CEr, the triangle of vertices A, B, C are equal to 1.

Consider points A=(1,0,1) and B=(0,1,0) fasa and r [x+y=1 (==y+l and lines S: a) There exists C Er, such that A, B, C are collinear b) For all points CES, A,B,C are collinear 2) For all points CEr, the triangle of vertices A, B, C are equal to 1.

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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Question

The correct answer is A but why can’t it be B , also I can’t seem to understand the correct way to do it

Consider points A = (1,0,1) and B=(0, 1, 0)
and ri
face
{ x+y=1
(z=y+l
and lines S:
a) There exists C Er, such that A, B, C are collinear
b) For all points CES, A, B, C are collinear
2) For all points CEr, the triangle of vertices A, B, C are equal to 1.

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