Consider an RL circuit consisting of an inductor with an inductance of L henry (H) and a resistor with a resistance of Rohms (2) driven by a voltage of E(t) volts V). Given the voltage drop across the resistor is ER = RI, and across the L(dI/dt), Kirchhoff's Law gives nductor is EL (t) = = ER(t) Now suppose an RL circuit with a 62 resistor and a 0.06H inductor is driven by a onstant voltage E(t) = sin(130t) V. If the initial resistor current is I(0) = 0A, - nd the current I and the voltages across the inductor EL and the resistor ER in erms of time t. = EL(t) = - = L dI dt + RI = E(t) A V V
Consider an RL circuit consisting of an inductor with an inductance of L henry (H) and a resistor with a resistance of Rohms (2) driven by a voltage of E(t) volts V). Given the voltage drop across the resistor is ER = RI, and across the L(dI/dt), Kirchhoff's Law gives nductor is EL (t) = = ER(t) Now suppose an RL circuit with a 62 resistor and a 0.06H inductor is driven by a onstant voltage E(t) = sin(130t) V. If the initial resistor current is I(0) = 0A, - nd the current I and the voltages across the inductor EL and the resistor ER in erms of time t. = EL(t) = - = L dI dt + RI = E(t) A V V
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Now suppose an RL circuit with a 6Ω resistor and a 0.06H inductor is driven by a constant voltage E(t)=sin(130t)V. If the initial resistor current is I(0)=0A, find the current I and the voltages across the inductor EL and the resistor ER in terms of time t.
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