Consider an ionic compound, MX,, composed of generic metal M and generic gaseous halogen X. • The enthalpy of formation of MX, is AH; = -605 kJ/mol. • The enthalpy of sublimation of M is A Hsub = 129 kJ/mol. • The first, second, and third ionization energies of M are IE, = 691 kJ/mol, IE2 = 1581 kJ/mol, and IE3 = 2627 kJ/mol. • The electron affinity of X is AHEA = -361 kJ/mol. (Refer to the hint). • The bond energy of X, is BE = 163 kJ/mol. Determine the lattice energy of MX,. kJ/mol AH attice

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### Determining the Lattice Energy of MX₃

Consider an ionic compound, MX₃, composed of a generic metal M and a generic gaseous halogen X. The given thermodynamic data includes:

- **Enthalpy of formation of MX₃ (\( \Delta H_f \))**: \(-605 \, \text{kJ/mol}\).
- **Enthalpy of sublimation of M (\( \Delta H_{\text{sub}} \))**: \(129 \, \text{kJ/mol}\).
- **Ionization energies of M**:
  - First ionization energy (\( \text{IE}_1 \)): \(691 \, \text{kJ/mol}\).
  - Second ionization energy (\( \text{IE}_2 \)): \(1581 \, \text{kJ/mol}\).
  - Third ionization energy (\( \text{IE}_3 \)): \(2627 \, \text{kJ/mol}\).
- **Electron affinity of X (\( \Delta H_{\text{EA}} \))**: \(-361 \, \text{kJ/mol}\).
- **Bond energy of X₂ (BE)**: \(163 \, \text{kJ/mol}\).

To determine the lattice energy (\( \Delta H_{\text{lattice}} \)) of MX₃, combine these values according to Hess's Law and the Born-Haber cycle.

\[ \Delta H_{\text{lattice}} = \text{[calculated value]} \, \text{kJ/mol} \]

### Calculation Steps

1. **Atomization of metal and nonmetal**: Convert solid M to gaseous M and dissociate X₂ to X:
   - Sublimation of M.
   - Half the bond energy for the dissociation of X₂.

2. **Ionization Energies**: Add up the energies required to remove electrons from M to form M³⁺.

3. **Electron Affinity**: Consider the energy change when X gains electrons.

4. **Combine**: Use these values to calculate the lattice energy through the energy conservation equation of the Born-Haber cycle.

\[ \Delta H_{\text{lattice}} = - \Delta H_f + \Delta H_{\text{sub}} + \text{IE}_1 + \text{IE}_2 + \text{IE}_3 + \Delta H_{\text{EA}} + \
Transcribed Image Text:### Determining the Lattice Energy of MX₃ Consider an ionic compound, MX₃, composed of a generic metal M and a generic gaseous halogen X. The given thermodynamic data includes: - **Enthalpy of formation of MX₃ (\( \Delta H_f \))**: \(-605 \, \text{kJ/mol}\). - **Enthalpy of sublimation of M (\( \Delta H_{\text{sub}} \))**: \(129 \, \text{kJ/mol}\). - **Ionization energies of M**: - First ionization energy (\( \text{IE}_1 \)): \(691 \, \text{kJ/mol}\). - Second ionization energy (\( \text{IE}_2 \)): \(1581 \, \text{kJ/mol}\). - Third ionization energy (\( \text{IE}_3 \)): \(2627 \, \text{kJ/mol}\). - **Electron affinity of X (\( \Delta H_{\text{EA}} \))**: \(-361 \, \text{kJ/mol}\). - **Bond energy of X₂ (BE)**: \(163 \, \text{kJ/mol}\). To determine the lattice energy (\( \Delta H_{\text{lattice}} \)) of MX₃, combine these values according to Hess's Law and the Born-Haber cycle. \[ \Delta H_{\text{lattice}} = \text{[calculated value]} \, \text{kJ/mol} \] ### Calculation Steps 1. **Atomization of metal and nonmetal**: Convert solid M to gaseous M and dissociate X₂ to X: - Sublimation of M. - Half the bond energy for the dissociation of X₂. 2. **Ionization Energies**: Add up the energies required to remove electrons from M to form M³⁺. 3. **Electron Affinity**: Consider the energy change when X gains electrons. 4. **Combine**: Use these values to calculate the lattice energy through the energy conservation equation of the Born-Haber cycle. \[ \Delta H_{\text{lattice}} = - \Delta H_f + \Delta H_{\text{sub}} + \text{IE}_1 + \text{IE}_2 + \text{IE}_3 + \Delta H_{\text{EA}} + \
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