Consider a uniform chain of length a initially with a part of length b hanging over the edge of a table and the remaining part in length (a – b) rolled up on the shore. Find the velocity and acceleration of the part of hanging chain as a function of its length and the speed and acceleration when the last link leaves the end of the table.
Consider a uniform chain of length a initially with a part of length b hanging over the edge of a table and the remaining part in length (a – b) rolled up on the shore. Find the velocity and acceleration of the part of hanging chain as a function of its length and the speed and acceleration when the last link leaves the end of the table.
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![Consider a uniform chain of length a initially with a part of length b hanging over the edge of a table
and the remaining part in length (a – b) rolled up on the shore. Find the velocity and acceleration of
the part of hanging chain as a function of its length and the speed and acceleration when the last link
leaves the end of the table.
y? = 29(y³ – b³)/3y²
ÿ = g – 29(y3 – b³)/3y³
%3D
ans.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F014cf8d4-5178-467b-a804-407eef5603c8%2Ffca5d6a1-16da-4739-9b11-fa4921f3aab3%2Fafq6lqr_processed.png&w=3840&q=75)
Transcribed Image Text:Consider a uniform chain of length a initially with a part of length b hanging over the edge of a table
and the remaining part in length (a – b) rolled up on the shore. Find the velocity and acceleration of
the part of hanging chain as a function of its length and the speed and acceleration when the last link
leaves the end of the table.
y? = 29(y³ – b³)/3y²
ÿ = g – 29(y3 – b³)/3y³
%3D
ans.
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