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Consider a uniform chain of length a initially with a part of length b hanging over the edge of a table
and the remaining part in length (a – b) rolled up on the shore. Find the velocity and acceleration of
the part of hanging chain as a function of its length and the speed and acceleration when the last link
leaves the end of the table.
y? = 29(y³ – b³)/3y²
ÿ = g – 29(y3 – b³)/3y³
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