Consider a small ferry that can accommodate cars and buses. The toll for cars is $3, and the toll for buses is $10. Let X and Y denote the number of cars and buses, respectively, carried on a single trip. Suppose the joint distribution of X and Y is as given in the table below. P(x,y) 1. 2 0.025 0.015 0.010 1 0.050 0.030 0.020 0.060 0.075 0.050 0.150 0.090 0.060 4 0.100 0.060 0.040 5 0.050 0.030 0.085 Compute the expected revenue from a single trip. (Round your answer to two decimal places.) Need Help? Read It

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Consider a small ferry that can accommodate cars and buses. The toll for cars is $3, and the toll for buses is $10. Let \( X \) and \( Y \) denote the number of cars and buses, respectively, carried on a single trip. Suppose the joint distribution of \( X \) and \( Y \) is as given in the table below.

\[
\begin{array}{c|ccc}
p(x,y) & y=0 & y=1 & y=2 \\
\hline
x=0 & 0.025 & 0.015 & 0.010 \\
x=1 & 0.050 & 0.030 & 0.020 \\
x=2 & 0.060 & 0.075 & 0.050 \\
x=3 & 0.150 & 0.090 & 0.060 \\
x=4 & 0.100 & 0.060 & 0.040 \\
x=5 & 0.050 & 0.030 & 0.085 \\
\end{array}
\]

Compute the expected revenue from a single trip. (Round your answer to two decimal places.)

\$ [ ]

Need Help?
- **Read It** (button)

**Explanation:**

This table represents the joint probability distribution of the number of cars \( X \) and the number of buses \( Y \) carried on a single trip by a ferry. Each cell in the table provides the probability of a specific combination of \( X \) cars and \( Y \) buses occurring.

To compute the expected revenue from a single trip, multiply each possible revenue outcome by its corresponding probability and sum the results. The revenue for each combination is calculated by using the formula:

\[
\text{Revenue} = 3X + 10Y
\]

where \( 3X \) is the total revenue from cars and \( 10Y \) is the total revenue from buses. Then, compute the expected value with:

\[
\text{Expected Revenue} = \sum p(x,y) \times (3X + 10Y)
\] 

Fill in the expected revenue calculation to get the final result.
Transcribed Image Text:Consider a small ferry that can accommodate cars and buses. The toll for cars is $3, and the toll for buses is $10. Let \( X \) and \( Y \) denote the number of cars and buses, respectively, carried on a single trip. Suppose the joint distribution of \( X \) and \( Y \) is as given in the table below. \[ \begin{array}{c|ccc} p(x,y) & y=0 & y=1 & y=2 \\ \hline x=0 & 0.025 & 0.015 & 0.010 \\ x=1 & 0.050 & 0.030 & 0.020 \\ x=2 & 0.060 & 0.075 & 0.050 \\ x=3 & 0.150 & 0.090 & 0.060 \\ x=4 & 0.100 & 0.060 & 0.040 \\ x=5 & 0.050 & 0.030 & 0.085 \\ \end{array} \] Compute the expected revenue from a single trip. (Round your answer to two decimal places.) \$ [ ] Need Help? - **Read It** (button) **Explanation:** This table represents the joint probability distribution of the number of cars \( X \) and the number of buses \( Y \) carried on a single trip by a ferry. Each cell in the table provides the probability of a specific combination of \( X \) cars and \( Y \) buses occurring. To compute the expected revenue from a single trip, multiply each possible revenue outcome by its corresponding probability and sum the results. The revenue for each combination is calculated by using the formula: \[ \text{Revenue} = 3X + 10Y \] where \( 3X \) is the total revenue from cars and \( 10Y \) is the total revenue from buses. Then, compute the expected value with: \[ \text{Expected Revenue} = \sum p(x,y) \times (3X + 10Y) \] Fill in the expected revenue calculation to get the final result.
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