Consider a skydiver falling towards the Earth. Air friction acts to oppose their motion. At some point the skydiver reaches their terminal speed: their constant maximum speed (before they open the parachute). Before and after terminal speed is reached, what can you say about the relationship between the force of air friction and the force of gravity? Briefly explain.
Q: A 35.0-kg child swings in a swing supported by two chains, each 3.06 m long. The tension in each…
A: Given, Mass of child = 35 Length of chains = 3.6 m Tension = 434 N (a) child's speed at lowest…
Q: A spherical raindrop 3.5 mm in diameter falls through a vertical distance of 3700 m. Take the…
A: The solution for this question has been given below...
Q: AN OBJECT WITH A MASS OF 0.980 Kg and a frontal area of 0.0400 m^2 is falling straight down. the…
A:
Q: Walking without slipping requires a static friction force between your feet (or footwear) and the…
A: When we walk without slipping, one of our foot pushes the floor. According to Newton’s 3rd law, the…
Q: A person pushes a box of mass m = 25 kg in a straight line along a rough floor. The applied force F…
A:
Q: A 60 kg skydiver can be modeled as a rectangular "box" with dimensions 22 cm × 40 cm × 1.8 m. What…
A: The expression for terminal speed is vT=2mgρACd Area of the sky driver experience the air resistance…
Q: (a) A sphere made of rubber has a density of 1.04 g/cm and a radius of 9.00 cm. It falls through air…
A:
Q: Question 5.45
A:
Q: A book resting on a sheet of ice is given an initial speed vi in the +x-direction. The coefficient…
A: Given quantities: initial velocity = vi coefficient of kinetic friction = μk acceleration due to…
Q: You are visiting your cousins for Christmas in New Hampshire where it is freezing. They are crazy.…
A: Applying Newton's second law on the sledge, ∑Fx=mgsin20°=ma [1]∑Fy=N-mgcos20°=0 [2] From…
Q: An object weighing 4.0 N falls from rest subject to a frictional drag force given by Fdrag - bv…
A: Weight of object (w) = 4 N Fdrag = b v2where , b = 3 N(ms2)
Q: as the speed of the turntable increases until it reaches a rate of 60 revolutions per minute and…
A: Given:- The distance of the coin from the center of the turntabled = 0.2 m.The coin remains in…
Q: Hawks soar in search of prey and then fold their wings and drop like a rock from the sky on their…
A: Since you have posted a question with a multiple sub parts, we will solve first three sub - parts…
Q: A raindrop with radius R= 1.6 mm falls from a cloud that is at height h = 1200 m above the ground.…
A: Given: The radius of the drop is 1.6 mm. The height of the cloud is 1200 m. The density of water is…
Q: What effect does horizontal velocity have on time of flight for a particle undergoing projectile…
A: “Since you have asked multiple question, we will solve the first question for you. If you want any…
Q: Why do Astronauts experience the feeling of weightlessness in orbit? At the Shuttle's altitude, the…
A: A person will feel weightless/free fall whenever there is no force to counter the force of gravity.…
Q: A 39.0-kg child swings in a swing supported by two chains, each 2.98 m long. The tension in each…
A: The mass of the child: The length of the chains: The tension in each chain at the lowest point:
Q: You are driving your car through a roundabout that has a radius of 9.0 m. Your physics textbook is…
A:
Q: A 5.7-kg rock and a 4.6 x 10-4-kg pebble are held near the surface of the earth. (a) Determine the…
A: Mr = 5.7 kgMp = 4.6 x 10-4 kgMr - mass of the rockMp - mass of the pebble
Q: In an old-fashioned amusement park ride, passengers stand inside a 4.6-m-diameter hollow steel…
A: Given: diameter of the cylinder, d=4.6 m co-efficient of static friction range, μs=0.60-1.0…
Q: (a) A sphere made of rubber has a density of 0.940 g/cm³ and a radius of 8.00 cm. It falls through…
A:
Q: A 1800 kgkg car starts from rest and drives around a flat 50-mm-diameter circular track. The forward…
A:
Q: A car is rounding a tight curve on a winding road. If the radius of curvature of this curve is 10.0…
A: Given data The gives the radius of the road is R = 10 m The static friction is given as μs = 0.80.…
Q: Sam has a mass of 116kg, he attempts to see how high he can jump by performing a standing high jump.…
A:
Q: An airplane maintains a constant speed of 277 m/s as it travels around a vertical circular loop…
A: Given:
Q: A box (400 kg) sits inside the trailer of a semitruck traveling at a speed of 25 m/s (~ 55 mph).…
A: As per the guide lines first three sub parts are answered. Kindly post the remaining question as a…
Q: It was a snow day, so Eric and some friends went sledding. He boarded his 60-inch sled and descended…
A:
Q: g up a grade of 15 with an initial velocity of 30 m/s. The coefficient of static friction between…
A: GivenAngle, θ=15°Initial velocity, u=30 m/sCoefficient of static friction between the tires and the…
Q: A modern race car is designed so that the passing air pushes down on it, allowing the car to travel…
A:
Q: The coefficient of static friction between an 8 kg box at rest and a 35° inclined plane is 0.70.…
A:
Step by step
Solved in 2 steps
- On Mars, the gravitational field constant is g = 3.7 N/kg. 1. When the object does encounter the atmosphere of Mars and reaches terminal velocity, what would the free-body diagram look like? Please label the forces involved.Suppose a car rounds a curve at a constant speed of 13 m/s. The curve is a circular arc with a radius of 100 m. Ignore air friction initially. (a) What is the magnitude and direction of the horizontal force that the road must exert on the car to keep it moving along the curve? Express this magnitude as a fraction of the car’s weight. The magnitude of the horizontal force is _______∣F→g∣|. The direction is (Choose one) Horizontal and parallel to the direction the car turns to Vertical and perpendicular to the direction the car turns to vertical and parallel to the direction the car turns to horizontal and perpendicular to the direction the car turns to (b) Now suppose that air friction is not zero, but is about half the result that you calculated for part (a). Must the force that the road exerts on the car increase in magnitude compared to the no-drag case? (Choose )Yes or No Must it change its direction? (Choose) Yes Or NoThe drag force for falling objects due to air friction depends on the velocity of the object and is given by the equation [Fdrag = bv] where b is a constant that depends on the fluid through which the object moves and the radius of the object. (a) Find the terminal speed (in m/s) of an object of mass 54 kg for which b = 17 kg/s. (b) Will the terminal speed be different if the object's initial speed is different? Yes or No?
- A parachutist wants to design a parachute, such that a person weighing 150 lbs(667N) descends at a rate of 5.00 mph(2.23 m/s). To calculate the drag coefficient in kg/m, is the way to conceptualize the solution: 1. At terminal velocity the drag force equals the force of gravity. Since the net forces are zero, there is no acceleration and the velocity is constant. 2. The drag constant b is not 1. It comes from the terminal velocity equation: V_term = square root(mg/b) If you know the weight mg and the terminal velocity, then you can solve for b. Please help me to derive the solution by helping me to understand better. I understand point 1. But I don't understand clearly point 2?Problem 2: Princess Peach is competing in a Mario Kart race on Rainbow Road. Rainbow Road has no rails, so Peach has to be careful taking turns to make sure she doesn't fall off. There is a notoriously difficult turn on the track made up of a portion of a circle 120m in diameter. The road is angled at 30°. The track has a friction coefficient of μ = .40. Given that Peach and the car weigh 800 kg. a) Draw a free-body diagram for the car on the road. b) What is the magnitude of the normal force, and what angle does it make with the horizontal? c) Repeat part b for the the friction force d) How fast can Peach take the turn without flying or falling off the track?. a. Consider two parachutists, a heavy person and a light person, who jump from the same altitude with parachutes of the same size. Which person reaches terminal speed first? Which person has the greater terminal speed? Which person reach the ground first? If there were no air resistance, as on the moon, how would your answers to these questions differ?
- A 35.0-kg child swings in a swing supported by two chains, each 2.98 m long. The tension in each chain at the lowest point is 440 N. (a) Find the child's speed at the lowest point.m/s(b) Find the force exerted by the seat on the child at the lowest point. (Ignore the mass of the seat.)N (upward)The mass of a sports car is 1100 kg. The shape of the car is such that the aerodynamic drag coefficient is 0.250 and the frontal area is 2.20 m2. Neglecting all other sources of friction, calculate the initial acceleration of the car, if it has been traveling at 80 km/h and is now shifted into neutral and is allowed to coast. (Take the density of air to be 1.295 kg/m3.) Answer:_____m/s2A racquetball has a radius of 0.0295 m. The drag coefficient of the ball is 0.35, and the density of the air is 1.29 kg/m3. What would be the terminal speed for the racquetball if it were dropped from a very high cliff, assuming it has a mass of 0.0394 kg?
- A 60 kg skydiver falls, beginning at rest. This isn't an ordinary skydive though, because it's taking place on an alien planet where g = 8 m/s2. The drag force on the skydiver is given by FD = -0.14 v (N). Calculate the speed of the skydiver after they have fallen for 322 s, in m/s. (Please answer to the fourth decimal place - i.e 14.3225)A motorcyclist in the Globe of Death, pictured here, rides in a 2.2-m-radius vertical loop. To keep control of the bike, the rider wants the normal force on his tires at the top of the loop to equal or exceed his and the bike’s combined weight. What is the minimum speed at which the rider can take the loop?During the 400 m race in question 5, Callie is now in the homestretch. Assume that the density of the air is 1.2 kg/m, that Callie’s cross-sectional area is 0.5 m2, and that her coefficient of drag is 1.1. Her velocity is still 8 m/s, but she now has a 2 m/s tailwind. How large is the drag force acting on Callie now?