A parachutist  wants to design a parachute, such that a person weighing 150 lbs(667N) descends at a rate of 5.00 mph(2.23 m/s). To calculate the drag coefficient in kg/m, is the way to conceptualize the solution: 1. At terminal velocity the drag force equals the force of gravity. Since the net forces are zero, there is no acceleration and the velocity is constant.   2. The drag constant b is not 1. It comes from the terminal velocity equation: V_term  = square root(mg/b) If you know the weight mg and the terminal velocity, then you can solve for b.   Please help me to derive the solution by helping me to understand better.  I understand point 1.  But I don't understand clearly point 2?

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The horse pulls the cart and the cart pulls the horse in response as per Newton third law. So the big question is, “Don’t the two forces cancel each other? How does the cart accelerate?”