Consider a situation where blood flows through a section of a horizontal artery that is partially blocked by a reservoir along the wall of the artery. A hemoglobin molecule moves from the narrow region to the wider region. What happens to the pressure acting on the molecule? Explain with fundamentals of fluid physics.
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Consider a situation where blood flows through a section of a horizontal artery that is partially blocked by a reservoir along the wall of the artery. A hemoglobin molecule moves from the narrow region to the wider region. What happens to the pressure acting on the molecule? Explain with fundamentals of fluid physics.
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- As a person breathes, during the inhale part of the cycle air moves down the windpipe (bronchus) and through a constriction where the air speed doubles. If the air is traveling 41 cm/s before the constriction and we treat air as an incompressible fluid, determine the pressure drop in the constriction. Use the density of air as 1.29 kg/m3.An ideal fluid is flowing with a speed of 12 cm/s through a pipe of diameter 5 cm. The pipe splits into three smaller pipes, each with a diameter of 2 cm. What is the speed of the fluid in the smaller pipes?A small blood vessels near the skin surface has a radius of 10um, a length of 1um and the pressure drop along the blood vessel is 2.50pa.The viscosity of blood is 0.0027pa.s. i. What is the volume flow rate of blood through this blood vessel. What is the velocity of blood flow? ii.Vasodilation causes the radius of this blood vessel to increase to 12um, while leaving the pressure drop along the vessel unchanged? What is the velocity of blood flow?
- There is a maximum depth at which a diver can breathe through a snorkel tube because as the depth increases, so does the pressure difference, which tends to collapse the diver’s lungs. Since the snorkel connects the air in the lungs to the atmosphere at the surface, the pressure inside the lungs is atmospheric pressure. What is the external–internal pressure difference when the diver’s lungs are at a depth of 6.1 m (about 20 ft)? Assume that the diver is in freshwater. (A scuba diver breathing from compressed air tanks can operate at greater depths than can a snorkeler, since the pressure of the air inside the scuba diver’s lungs increases to match the external pressure of the water.)Blood pressure is measured when the blood is pumping (systolic) and when the heart is resting (diastolic). When pressure readings are given, the systolic is given first, and healthy blood pressure is around 120 over 80 mm Hg. Recall the density of mercury is 13.6 × 103 kg/m3. a. Suppose you have a blood pressure reading of 116 over 82 mm Hg. What is your systolic pressure, in newtons per meter squared? b. Suppose you have a blood pressure reading of 116 over 82 mm Hg. What is your diastolic pressure, in newtons per meter squared?In order to take a nice relaxing bath after this final, you fill up a bathtub with warm water. To fill the tub, water travels at 9 m/s in a pipe under your house. The faucet (where the water exits into the tub) in your house has a diameter twice that of the pipe under your house. The water pressure in the pipe/faucet is the same everywhere. (a) What is the height of your faucet, relative to the pipe under your house? (b) Let's do some special cases sensemaking! If the diameter of the faucet were the same as the diameter of the pipe under your house and the pressure was the same everywhere, what would the height differ ence need to be? explain.
- In a hydraulic system, a boy of mass m is standing on one of the movable pistons having a rectangular shape with sides a and b. (a) What is the pressure in the hydraulic fluid? (b) What is the force exerted on another movable piston that has the form of a square with side a? please provide step by step answer and provide analytical (symbolic) solutions. Only notations, not moles.The Venturi tube discussed in Example 14.8 and shown in figure may be used as a fluid flowmeter. Suppose the device is used at a service station to measure the flow rate of gasoline (p = 7 X10² kg/m³) through a hose having an outlet radius of 1.2 cm. If the difference in pressure is %3D measured to be (P1 - P2 = 1.2 kPa) and the radius of the inlet tube to the meter is 2.4 cm. (a) Find the speed V2 of the gasoline as it leaves the hose. (b) Find the fluid flow rate in cubic meters per second.Fish can adjust their buoyancy with an organ called the swim bladder. The swim bladder is a flexible gas-filled sac; the fish can increase or decrease the amount of gas in the swim bladder so that it stays neutrally buoyant—neither sinking nor floating. Suppose the fish is neutrally buoyant at some depth and then goes deeper. What needs to happen to the volume of air in the swim bladder? Will the fish need to add or remove gas from the swim bladder to maintain its neutral buoyancy?
- Question 7 of 18 You come across an open container that is filled with two liquids. Since the two liquids have different densities, there is a distinct separation between them. Water, which has a density of pw = 1.00 × 10³ kg/m³, fills the lower portion of the container to a depth of 0.200 m. The fluid that is floating on top of the water is 0.307 m deep. If the absolute pressure on the bottom of the container is 1.049 × 10° Pa, what is the density, pi, of the unknown fluid? The acceleration due to gravity is g = 9.81 m/s² and atmospheric pressure is Po = 1.013 x 10° Pa. Pi = kg/m3Consider a 3.9 kg freshwater fish whose tissues have an average density of 1050 kg/m^3. Part A To what volume in mL must the swim bladder be inflated for the fish to be neutrally buoyant at the surface? Part B What volume of air would have to be added to the swim bladder for the fish to remain neutrally buoyant at a depth of 20 m?You come across an open container that is filled with two liquids. Since the two liquids have different densities, there is a distinct separation between them. Water, which has a density of pw = 1.00 x 10° kg/m², fills the lower portion of the container to a depth of 0.206 m. The fluid that is floating on top of the water is 0.314 m deep. If the absolute pressure on the bottom of the container is 1.049 × 10° Pa, what is the density, p1, of the unknown fluid? The acceleration due to gravity is g = 9.81 m/s² and atmospheric pressure is Po = 1.013 × 10° Pa. Pi = kg/m³