Please asap ### Problem StatementA large, bronze statue of Newton falls from the deck of a ship and sinks until it rests on the bottom of the ocean. The density of bronze is \( 8.2 \times 10^3 \, \text{kg/m}^3 \), the density of seawater is \( 1.02 \times 10^3 \, \text{kg/m}^3 \), and the volume of the statue is \( 0.14 \, \text{m}^3 \). When the statue reaches a depth of 20 meters, what is the magnitude of the buoyancy force on the statue (in N)?### SolutionTo determine the buoyancy force acting on the statue, we can use Archimedes' principle, which states that the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. The formula for buoyancy force (\( F_b \)) is:\[ F_b = \rho_{\text{fluid}} \times V_{\text{object}} \times g \]Where:- \( \rho_{\text{fluid}} \) is the density of the fluid (seawater in this case),- \( V_{\text{object}} \) is the volume of the object (the statue),- \( g \) is the acceleration due to gravity (approximately \( 9.8 \, \text{m/s}^2 \)).Given data:- Density of seawater, \( \rho_{\text{fluid}} = 1.02 \times 10^3 \, \text{kg/m}^3 \)- Volume of the statue, \( V_{\text{object}} = 0.14 \, \text{m}^3 \)- Acceleration due to gravity, \( g = 9.8 \, \text{m/s}^2 \)Substituting the values into the formula:\[ F_b = 1.02 \times 10^3 \, \text{kg/m}^3 \times 0.14 \, \text{m}^3 \times 9.8 \, \text{m/s}^2 \]Calculating the buoyant force:\[ F_b = 1.02 \times 0.14 \times 9.8 \times 10^3 \, \

Name: Please asap ### Problem StatementA large, bronze statue of Newton fall
Uploaded: 2024-03-20T06:51:10.000Z
Channel: Bartleby
Description: Please asap ### Problem StatementA large, bronze statue of Newton falls from the deck of a ship and sinks until it rests on the bottom of the ocean. The density of bronze is \( 8.2 \times 10^3 \, \text{kg/m}^3 \), the density of seawater is \( 1.02 \