Consider a series RC circuit as in the figure below for which R = 6.70 M2, C = 4.70 μF, and = 25.5 V. + E S R (a) Find the time constant of the circuit. 31.49 (b) Find the maximum charge on the capacitor after the switch is thrown closed. 1.1985e-4 X What is the current in the circuit when the capacitor has reached its maximum charge? μC (c) Find the current in the resistor 10.0 s after the switch is closed. MA
Consider a series RC circuit as in the figure below for which R = 6.70 M2, C = 4.70 μF, and = 25.5 V. + E S R (a) Find the time constant of the circuit. 31.49 (b) Find the maximum charge on the capacitor after the switch is thrown closed. 1.1985e-4 X What is the current in the circuit when the capacitor has reached its maximum charge? μC (c) Find the current in the resistor 10.0 s after the switch is closed. MA
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![**RC Circuit Analysis**
Consider a series RC circuit as shown in the diagram. The values for the components of the circuit are as follows:
- Resistance (R) = 6.70 MΩ
- Capacitance (C) = 4.70 μF
- Electromotive Force (ℰ) = 25.5 V
**Tasks:**
(a) **Find the time constant of the circuit.**
The time constant (τ) is calculated using the formula:
\[ \tau = R \times C \]
The time constant is:
\[ \boxed{31.49} \, \text{s} \]
(b) **Find the maximum charge on the capacitor after the switch is thrown closed.**
\[ Q_{\text{max}} = C \times \mathcal{E} \]
The attempted calculation shows an incorrect value:
\[ 1.1985 \times 10^{-4} \, \text{μC (incorrect)} \]
The statement, "What is the current in the circuit when the capacitor has reached its maximum charge?" is given, which indicates a follow-up question on the same topic.
(c) **Find the current in the resistor 10.0 seconds after the switch is closed.**
\[ I(t) = \frac{V}{R} e^{-t/\tau} \]
Fill in the current value:
\[ \boxed{ \, \text{µA} } \]
**Diagram Details:**
- The circuit diagram includes a resistor (R) and a capacitor (C) connected in series, with a switch (S) that can be closed to complete the circuit.
- The power source provides a potential difference represented by ℰ, with the positive terminal connected to the capacitor.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F75efe16f-f4aa-4987-9727-1ee0c2946a7c%2Fa587ff14-66c2-449d-b748-35eaf14afbd7%2Fsip20f9_processed.png&w=3840&q=75)
Transcribed Image Text:**RC Circuit Analysis**
Consider a series RC circuit as shown in the diagram. The values for the components of the circuit are as follows:
- Resistance (R) = 6.70 MΩ
- Capacitance (C) = 4.70 μF
- Electromotive Force (ℰ) = 25.5 V
**Tasks:**
(a) **Find the time constant of the circuit.**
The time constant (τ) is calculated using the formula:
\[ \tau = R \times C \]
The time constant is:
\[ \boxed{31.49} \, \text{s} \]
(b) **Find the maximum charge on the capacitor after the switch is thrown closed.**
\[ Q_{\text{max}} = C \times \mathcal{E} \]
The attempted calculation shows an incorrect value:
\[ 1.1985 \times 10^{-4} \, \text{μC (incorrect)} \]
The statement, "What is the current in the circuit when the capacitor has reached its maximum charge?" is given, which indicates a follow-up question on the same topic.
(c) **Find the current in the resistor 10.0 seconds after the switch is closed.**
\[ I(t) = \frac{V}{R} e^{-t/\tau} \]
Fill in the current value:
\[ \boxed{ \, \text{µA} } \]
**Diagram Details:**
- The circuit diagram includes a resistor (R) and a capacitor (C) connected in series, with a switch (S) that can be closed to complete the circuit.
- The power source provides a potential difference represented by ℰ, with the positive terminal connected to the capacitor.
Expert Solution
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Step 1
Given,
R = 6.70 MΩ = 6.70 x 106 Ω
C = 4.70 μF = 4.70 x 10-6 F
ε = 25.5 V
Step by step
Solved in 2 steps
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