Consider a series RC circuit as in the figure below for which R = 6.70 M2, C = 4.70 μF, and = 25.5 V. + E S R (a) Find the time constant of the circuit. 31.49 (b) Find the maximum charge on the capacitor after the switch is thrown closed. 1.1985e-4 X What is the current in the circuit when the capacitor has reached its maximum charge? μC (c) Find the current in the resistor 10.0 s after the switch is closed. MA

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**RC Circuit Analysis**

Consider a series RC circuit as shown in the diagram. The values for the components of the circuit are as follows:
- Resistance (R) = 6.70 MΩ
- Capacitance (C) = 4.70 μF
- Electromotive Force (ℰ) = 25.5 V

**Tasks:**

(a) **Find the time constant of the circuit.**

The time constant (τ) is calculated using the formula:
\[ \tau = R \times C \]

The time constant is:
\[ \boxed{31.49} \, \text{s} \]

(b) **Find the maximum charge on the capacitor after the switch is thrown closed.**

\[ Q_{\text{max}} = C \times \mathcal{E} \]
The attempted calculation shows an incorrect value:
\[ 1.1985 \times 10^{-4} \, \text{μC (incorrect)} \]

The statement, "What is the current in the circuit when the capacitor has reached its maximum charge?" is given, which indicates a follow-up question on the same topic.

(c) **Find the current in the resistor 10.0 seconds after the switch is closed.**

\[ I(t) = \frac{V}{R} e^{-t/\tau} \]

Fill in the current value:
\[ \boxed{ \, \text{µA} } \]

**Diagram Details:**

- The circuit diagram includes a resistor (R) and a capacitor (C) connected in series, with a switch (S) that can be closed to complete the circuit.
- The power source provides a potential difference represented by ℰ, with the positive terminal connected to the capacitor.
Transcribed Image Text:**RC Circuit Analysis** Consider a series RC circuit as shown in the diagram. The values for the components of the circuit are as follows: - Resistance (R) = 6.70 MΩ - Capacitance (C) = 4.70 μF - Electromotive Force (ℰ) = 25.5 V **Tasks:** (a) **Find the time constant of the circuit.** The time constant (τ) is calculated using the formula: \[ \tau = R \times C \] The time constant is: \[ \boxed{31.49} \, \text{s} \] (b) **Find the maximum charge on the capacitor after the switch is thrown closed.** \[ Q_{\text{max}} = C \times \mathcal{E} \] The attempted calculation shows an incorrect value: \[ 1.1985 \times 10^{-4} \, \text{μC (incorrect)} \] The statement, "What is the current in the circuit when the capacitor has reached its maximum charge?" is given, which indicates a follow-up question on the same topic. (c) **Find the current in the resistor 10.0 seconds after the switch is closed.** \[ I(t) = \frac{V}{R} e^{-t/\tau} \] Fill in the current value: \[ \boxed{ \, \text{µA} } \] **Diagram Details:** - The circuit diagram includes a resistor (R) and a capacitor (C) connected in series, with a switch (S) that can be closed to complete the circuit. - The power source provides a potential difference represented by ℰ, with the positive terminal connected to the capacitor.
Expert Solution
Step 1

Given,

R = 6.70 MΩ = 6.70 x 10Ω

C = 4.70 μF = 4.70 x 10-6 F

ε = 25.5 V

 

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