In the circuit of (Figure 1), each resistor represents a light bulb. Let R = R2 = R3 = RA = 4.56 N and let the Part G EMF be 8.98 V. Find the power dissipated in the bulb R3. Express your answer in watts. P = W Figure 1 of 1 R1 Part H R3 Find the power dissipated in the bulb R4. R2 Express your answer in watts. ? P = W
In the circuit of (Figure 1), each resistor represents a light bulb. Let R = R2 = R3 = RA = 4.56 N and let the Part G EMF be 8.98 V. Find the power dissipated in the bulb R3. Express your answer in watts. P = W Figure 1 of 1 R1 Part H R3 Find the power dissipated in the bulb R4. R2 Express your answer in watts. ? P = W
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![### Circuit Analysis and Power Dissipation
**Problem Description:**
In the circuit shown, each resistor represents a light bulb. The resistances are given as \( R_1 = R_2 = R_3 = R_4 = 4.56 \, \Omega \). The electromotive force (EMF) of the battery is \( 8.98 \, V \).
**Diagram Explanation:**
The schematic diagram depicts a circuit with an EMF source (battery) on the left side. The circuit includes four resistors:
- \( R_1 \) is in series with the battery.
- \( R_2 \), \( R_3 \), and \( R_4 \) are configured in a square formation where:
- \( R_2 \) is connected in parallel with the combination of \( R_3 \) and \( R_4 \) in series.
For the purpose of solving and understanding the circuit, we consider the following tasks:
**Tasks:**
1. **Part G:**
- **Objective:** Calculate the power dissipated in the bulb \( R_3 \).
- **Instructions:** Express the power (\( P \)) in watts (W).
2. **Part H:**
- **Objective:** Calculate the power dissipated in the bulb \( R_4 \).
- **Instructions:** Express the power (\( P \)) in watts (W).
**Formulas:**
- **Power Dissipation Formula:**
\[
P = I^2 \times R
\]
or
\[
P = \frac{V^2}{R}
\]
- **Total Resistance in Parallel:**
\[
\frac{1}{R_{\text{total}}} = \frac{1}{R_2} + \frac{1}{R_3 + R_4}
\]
By calculating the total current and voltage across each resistor, the power dissipated by each bulb can be determined accurately using the above equations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F768a66a2-bff7-4da2-8ed9-a0414e992096%2Fe27b9849-6c0e-4cf9-b4eb-f2689c0877b4%2Fpxpfg6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Circuit Analysis and Power Dissipation
**Problem Description:**
In the circuit shown, each resistor represents a light bulb. The resistances are given as \( R_1 = R_2 = R_3 = R_4 = 4.56 \, \Omega \). The electromotive force (EMF) of the battery is \( 8.98 \, V \).
**Diagram Explanation:**
The schematic diagram depicts a circuit with an EMF source (battery) on the left side. The circuit includes four resistors:
- \( R_1 \) is in series with the battery.
- \( R_2 \), \( R_3 \), and \( R_4 \) are configured in a square formation where:
- \( R_2 \) is connected in parallel with the combination of \( R_3 \) and \( R_4 \) in series.
For the purpose of solving and understanding the circuit, we consider the following tasks:
**Tasks:**
1. **Part G:**
- **Objective:** Calculate the power dissipated in the bulb \( R_3 \).
- **Instructions:** Express the power (\( P \)) in watts (W).
2. **Part H:**
- **Objective:** Calculate the power dissipated in the bulb \( R_4 \).
- **Instructions:** Express the power (\( P \)) in watts (W).
**Formulas:**
- **Power Dissipation Formula:**
\[
P = I^2 \times R
\]
or
\[
P = \frac{V^2}{R}
\]
- **Total Resistance in Parallel:**
\[
\frac{1}{R_{\text{total}}} = \frac{1}{R_2} + \frac{1}{R_3 + R_4}
\]
By calculating the total current and voltage across each resistor, the power dissipated by each bulb can be determined accurately using the above equations.
Transcribed Image Text:**Educational Content: Circuit Analysis and Power Dissipation**
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**Circuit Description**
In the circuit shown in the figure, each resistor represents a light bulb. Let \( R_1 = R_2 = R_3 = R_4 = 4.56 \, \Omega \) and let the EMF be 8.98 V.
**Figure Description**
The figure displays a circuit with four resistors (\( R_1, R_2, R_3, \) and \( R_4 \)). Resistors \( R_1 \) and \( R_2 \) are in series with the EMF source. Resistors \( R_3 \) and \( R_4 \) are parallel to each other and in series with the combination of \( R_1 \) and \( R_2 \).
---
**Part E**
Find the power dissipated in the bulb \( R_1 \).
- **Question:** Express your answer in watts.
- **Input Box:** Provide your answer for power \( P \) in watts.
**Part F**
Find the power dissipated in the bulb \( R_2 \).
- **Question:** Express your answer in watts.
- **Input Box:** Provide your answer for power \( P \) in watts.
---
To solve for the power dissipated, apply the formula \( P = I^2 R \) or \( P = \frac{V^2}{R} \), based on the configuration of the circuit and the given values. Make sure to calculate the total resistance and current accordingly for accurate results.
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