In the circuit of (Figure 1), each resistor represents a light bulb. Let R = R2 = R3 = RA = 4.56 N and let the Part G EMF be 8.98 V. Find the power dissipated in the bulb R3. Express your answer in watts. P = W Figure 1 of 1 R1 Part H R3 Find the power dissipated in the bulb R4. R2 Express your answer in watts. ? P = W

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### Circuit Analysis and Power Dissipation

**Problem Description:**

In the circuit shown, each resistor represents a light bulb. The resistances are given as \( R_1 = R_2 = R_3 = R_4 = 4.56 \, \Omega \). The electromotive force (EMF) of the battery is \( 8.98 \, V \).

**Diagram Explanation:**

The schematic diagram depicts a circuit with an EMF source (battery) on the left side. The circuit includes four resistors:
- \( R_1 \) is in series with the battery.
- \( R_2 \), \( R_3 \), and \( R_4 \) are configured in a square formation where:
  - \( R_2 \) is connected in parallel with the combination of \( R_3 \) and \( R_4 \) in series.

For the purpose of solving and understanding the circuit, we consider the following tasks:

**Tasks:**

1. **Part G:** 
   - **Objective:** Calculate the power dissipated in the bulb \( R_3 \).
   - **Instructions:** Express the power (\( P \)) in watts (W).

2. **Part H:** 
   - **Objective:** Calculate the power dissipated in the bulb \( R_4 \).
   - **Instructions:** Express the power (\( P \)) in watts (W).

**Formulas:**

- **Power Dissipation Formula:**
  \[
  P = I^2 \times R
  \]
  or
  \[
  P = \frac{V^2}{R}
  \]

- **Total Resistance in Parallel:**
  \[
  \frac{1}{R_{\text{total}}} = \frac{1}{R_2} + \frac{1}{R_3 + R_4}
  \]

By calculating the total current and voltage across each resistor, the power dissipated by each bulb can be determined accurately using the above equations.
Transcribed Image Text:### Circuit Analysis and Power Dissipation **Problem Description:** In the circuit shown, each resistor represents a light bulb. The resistances are given as \( R_1 = R_2 = R_3 = R_4 = 4.56 \, \Omega \). The electromotive force (EMF) of the battery is \( 8.98 \, V \). **Diagram Explanation:** The schematic diagram depicts a circuit with an EMF source (battery) on the left side. The circuit includes four resistors: - \( R_1 \) is in series with the battery. - \( R_2 \), \( R_3 \), and \( R_4 \) are configured in a square formation where: - \( R_2 \) is connected in parallel with the combination of \( R_3 \) and \( R_4 \) in series. For the purpose of solving and understanding the circuit, we consider the following tasks: **Tasks:** 1. **Part G:** - **Objective:** Calculate the power dissipated in the bulb \( R_3 \). - **Instructions:** Express the power (\( P \)) in watts (W). 2. **Part H:** - **Objective:** Calculate the power dissipated in the bulb \( R_4 \). - **Instructions:** Express the power (\( P \)) in watts (W). **Formulas:** - **Power Dissipation Formula:** \[ P = I^2 \times R \] or \[ P = \frac{V^2}{R} \] - **Total Resistance in Parallel:** \[ \frac{1}{R_{\text{total}}} = \frac{1}{R_2} + \frac{1}{R_3 + R_4} \] By calculating the total current and voltage across each resistor, the power dissipated by each bulb can be determined accurately using the above equations.
**Educational Content: Circuit Analysis and Power Dissipation**

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**Circuit Description**

In the circuit shown in the figure, each resistor represents a light bulb. Let \( R_1 = R_2 = R_3 = R_4 = 4.56 \, \Omega \) and let the EMF be 8.98 V.

**Figure Description**

The figure displays a circuit with four resistors (\( R_1, R_2, R_3, \) and \( R_4 \)). Resistors \( R_1 \) and \( R_2 \) are in series with the EMF source. Resistors \( R_3 \) and \( R_4 \) are parallel to each other and in series with the combination of \( R_1 \) and \( R_2 \).

---

**Part E**

Find the power dissipated in the bulb \( R_1 \).

- **Question:** Express your answer in watts.
- **Input Box:** Provide your answer for power \( P \) in watts.

**Part F**

Find the power dissipated in the bulb \( R_2 \).

- **Question:** Express your answer in watts.
- **Input Box:** Provide your answer for power \( P \) in watts.

---

To solve for the power dissipated, apply the formula \( P = I^2 R \) or \( P = \frac{V^2}{R} \), based on the configuration of the circuit and the given values. Make sure to calculate the total resistance and current accordingly for accurate results.
Transcribed Image Text:**Educational Content: Circuit Analysis and Power Dissipation** --- **Circuit Description** In the circuit shown in the figure, each resistor represents a light bulb. Let \( R_1 = R_2 = R_3 = R_4 = 4.56 \, \Omega \) and let the EMF be 8.98 V. **Figure Description** The figure displays a circuit with four resistors (\( R_1, R_2, R_3, \) and \( R_4 \)). Resistors \( R_1 \) and \( R_2 \) are in series with the EMF source. Resistors \( R_3 \) and \( R_4 \) are parallel to each other and in series with the combination of \( R_1 \) and \( R_2 \). --- **Part E** Find the power dissipated in the bulb \( R_1 \). - **Question:** Express your answer in watts. - **Input Box:** Provide your answer for power \( P \) in watts. **Part F** Find the power dissipated in the bulb \( R_2 \). - **Question:** Express your answer in watts. - **Input Box:** Provide your answer for power \( P \) in watts. --- To solve for the power dissipated, apply the formula \( P = I^2 R \) or \( P = \frac{V^2}{R} \), based on the configuration of the circuit and the given values. Make sure to calculate the total resistance and current accordingly for accurate results.
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