Consider a right tailed test with a = 0.15. What is the rejection region for this one-sided confidence bound at the 85% confidence level? (a) Z> 1.036 (b) Z < 1.356 (c) Z < 2.12 (d) Z> 1.96 (e) None of the above
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From the provided information,
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Confidence level = 85%
The test is right tailed.
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- H: H=3 versus H: u# 3 Since the 95% confidence interval (Choose one) Hr then H (Choose one) be rejected at the 0.05 level. contains does not contain Will/will notSuppose that you run a Regression Model and the Regression Coefficient for X has an associated p-value of 0.0070. At the 99% Confidence Level, is X significant? Enter a 1 into the blank below if X is significant and a O if it is not.An SRS of 450 high school seniors gained an average of x = 20.80 points in their second attempt at the SAT Mathematics exam. Assume that the change in score has a Normal distribution with standard deviation a = 54.81. We want to estimate the mean change in score in the population of all high school seniors. (a) Using the 68-95-99.7 Rule or the z-table (Table A), give a 68% confidence interval (a, b) for u based on this sample. H (Enter your answers rounded to three decimal places. If you are using Crunchlt, adjust the default precision under Preferences as necessary. See the instructional video on how to adjust precision settings.) a: (b) Based on your confidence interval in part (a), how certain are you that the mean change in score u in the population of all high school seniors is greater than 0? The interval does not contain 0, so we are 68% certain that the mean change in score in the population of all high school seniors is greater than 0. We cannot be certain at all. If we want…
- 2) (9.2) Suppose a random sample of 1001 Americans age 15 or older were asked "How much time do you spend eating or drinking per day?" Of the 1001 participants, the mean amount of time spent eating or drinking per day is 1.22 hours with a standard deviation of 0.65 hours. Determine a 99% confidence interval for the mean amount of time Americans age 15 or older spend eating or drinking each day.Determine the p-value corresponding to z for the observed level of the statistic in one-tailed tests (a) z= 1.64 (b) z = -1.64 (c) z= 2.76 (d) z = -2.76 (e) z = 0.00 (f) z = -1.645None
- A flu shot is administered during flu season. We look at the effect of the shot on individuals who received the shot versus those who did not. In a sample of 100 patients that received the flu shot, the average recovery time after being infected with the flu was 4 days with a standard deviation of 1 day. What is a 95% confidence interval for the population average recovery time? O (3.99.4.01) (3.80, 4.20)In a left-tailed hypothesis for a population mean where the population standard deviation is unknown, the test statistic for a random sample size 18 was calculated to be -4.0545. Determine the P-value for the test. XSuppose you sample six people on their number of visits to Chick-fil-A in a month given by variable Y. Y = 3,6,7,10,15,19 (A) What is the mean of Y? Standard Deviation of Y?(B) What is the Standard Error of Y?(C) Construct 90% and 95% Confidence Intervals for Y.
- In order to construct a confidence interval for the population variance, a random sample of n observations is drawn from a normal population. Use this information to find x²a/2, df and x²1-a/2, df under the following scenarios. (Round your answers to 3 decimal places. You may find it useful to reference the appropriate table: chi-square table or Ftable) X²al2,df a. A 95% confidence level with n = 9. b. A 95% confidence level with n = 40. c. A 99% confidence level with n = 9. d. A 99% confidence level with n = 40. X²1-a/2,dfAn SRS of 400 high school seniors gained an average of x = 21.87 points in their second attempt at the SAT Mathematics exam. Assume that the change in score has a Normal distribution with standard deviation o = 48.66. We want to estimate the mean change in score µ in the population of all high school seniors. (a) Using the 68-95-99.7 Rule or the z-table (Table A), give a 95% confidence interval (a, b) for u based on this sample. (Enter your answers rounded to three decimal places. If you are using CrunchIt, adjust the default precision under Preferences as necessary. See the instructional video on how to adjust precision settings.) a: b: (b) Based on your confidence interval in part (a), how certain are you that the mean change in score u in the population of all high school seniors is greater than 0? O The upper endpoint of the interval is larger than 0, so we are 95% certain that the mean change in score in the population of all high school seniors is greater than 0. O We cannot be…18
