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Consider a reaction A→B in a liquid phase with a second order reaction, contains 2 mol/L of A and enters the reactor with a flowrate of 1 mol/hr. Flow reactor to reach 75% conversion.

Consider a reaction A→B in a liquid phase with a second order reaction, contains 2 mol/L of A and enters the reactor with a flowrate of 1 mol/hr. Flow reactor to reach 75% conversion.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Plug flow reactor Problem 1 Consider a reaction A⇒B in a liquid phase with a second order reaction, kÃ=0.1 L/mol/hr. The feed contains 2 mol/L of A and enters the reactor with a flowrate of 1 mol/hr. Calculate the volume of a plug flow reactor to reach 75% conversion. Repeat the same calculation for first order and zero order reactions.
Transcribed Image Text:Plug flow reactor Problem 1 Consider a reaction A⇒B in a liquid phase with a second order reaction, kÃ=0.1 L/mol/hr. The feed contains 2 mol/L of A and enters the reactor with a flowrate of 1 mol/hr. Calculate the volume of a plug flow reactor to reach 75% conversion. Repeat the same calculation for first order and zero order reactions.
n = 0 -TA = k n = 1 -TA = KCA n = 2 -TA = KC² any n = -TA kC KT CAO Table 5.1 Performance Equations for nth-order Kinetics and A = 0 Plug Flow or Batch CAO - CA CAO KT = ln CAO CA kTCao = = In CAO CA (n − 1)Chokr= 8.1 Integral Table = XA 1 1-XA - CA ΧΑ 1-XA C₁ 1-n A0/ - 1 = (1 - XA)¹-n – 1 pX₂ (20) (3.12) dX (1 (3.16) dX (4=(x) In 1- X (3.29) 1- X x₁²01²²x²-1-²-²₂2-1-²X dX fax-x X 1- X KT CAO dX ²14xx - ² m (1 + ex) = ln + EX KkT= KT= KT = САО - СА CAO CAO - CA CA Note: for batch reactor t = t V for Plug flow reactor t = where V is the reactor volume and v is the volumetric flowrate V FAo = vCAO Mixed Flow (Cao – CA) - ÁO - CA CA = XA XA 1 - XA XA CA0(1-XA)² ΧΑ Cho (1 − XA)" (14a) (15)
Transcribed Image Text:n = 0 -TA = k n = 1 -TA = KCA n = 2 -TA = KC² any n = -TA kC KT CAO Table 5.1 Performance Equations for nth-order Kinetics and A = 0 Plug Flow or Batch CAO - CA CAO KT = ln CAO CA kTCao = = In CAO CA (n − 1)Chokr= 8.1 Integral Table = XA 1 1-XA - CA ΧΑ 1-XA C₁ 1-n A0/ - 1 = (1 - XA)¹-n – 1 pX₂ (20) (3.12) dX (1 (3.16) dX (4=(x) In 1- X (3.29) 1- X x₁²01²²x²-1-²-²₂2-1-²X dX fax-x X 1- X KT CAO dX ²14xx - ² m (1 + ex) = ln + EX KkT= KT= KT = САО - СА CAO CAO - CA CA Note: for batch reactor t = t V for Plug flow reactor t = where V is the reactor volume and v is the volumetric flowrate V FAo = vCAO Mixed Flow (Cao – CA) - ÁO - CA CA = XA XA 1 - XA XA CA0(1-XA)² ΧΑ Cho (1 − XA)" (14a) (15)
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