Consider a portion of a cell membrane that has a thickness of 7.50 nm and 1.2 um x 1.2 um in area. A measurement of the potential difference across the inner and outer surfaces of the membrar gives a reading of 87.3 mv. The resistivity of the membrane material is 1.30 x 10 0. m. (a) Determine the amount of current that flows through this portion of the membrane.
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- A copper wire of radius a = 0.334 mm has an aluminum jacket of outer radius b = 0.465 mm. There is a current i = 2.34 A in the composite wire. Take the resistivity for copper and aluminum to be 1.69 × 10802•m and 2.75 × 10-Q.m. Calculate the current in (a) the copper and (b) the aluminum. (c) If a potential difference V = 17.0 V between the ends maintains the current, what is the length in meters of the composite wire? (a) Number i (b) Number Units Units (c) Number UnitsAn aluminum wire with a diameter of 0.125 mm has a uniform electric field of 0.195 V/m imposed along its entire length. The temperature of the wire is 35.0°C. Assume one free electron per atom. (a) Use the information in this Table of Resistivities and Temperature Coefficients to determine the resistivity (in Ω · m) of aluminum at this temperature. (b) What is the current density (in MA/m2) in the wire? J =----- MA/m2 (c) What is the total current (in mA) in the wire? I =--------- mA (d) What is the drift speed of the conduction electrons? vd = ------µm/s (e) What potential difference must exist between the ends of a 1.70 m length of the wire to produce the stated electric field? ΔV = --------- VA current I =0.35 A flows through a cylindrical resistor made out of some unknown ceramic-like composite. The radius of the cylindrical body is 4.25 mm while the length is 1.65 cm. If the potential drop over the resistor is 7.54 V, what is the resistivity of the unknown ceramic material? (Answer in Ohm*m)
- A copper wire of radius a = 0.172 mm has an aluminum jacket of outer radius b = 0.231 mm. There is a current i = 1.58 A in the composite wire. Take the resistivity for copper and aluminum to be 1.69 × 10*Q-m and 2.75 × 10-°2-m. Calculate the current in (a) the copper and (b) the aluminum. (c) If a potential difference V = 10.4 V between the ends maintains the current, what is the length in meters of the composite wire? (a) Number i Units (b) Number i Units (c) Number i UnitsA copper wire of radius a = 0.240 mm has an aluminum jacket of outer radius b = 0.329 mm. There is a current i = 1.57 A in the composite wire. Take the resistivity for copper and aluminum to be 1.69 × 10-8Ω·m and 2.75 × 10-8Ω·m. Calculate the current in (a) the copper and (b) the aluminum. (c) If a potential difference V = 13.1 V between the ends maintains the current, what is the length in meters of the composite wire?In a physics project, you need a wire to electrically heat a cryostat. You decide to create one with materials you have lying around. You find a 29.0-g piece of copper. The resistivity of copper is 1.68 x 10-8 Ω.m, and its density is 8.9 g/cm3. You will need to use all of your copper to create a solid cylindrical wire that has a total resistance of 0.75 Ω.Determine how long your wire will be, and what its diameter will be.
- Part (a) I measure the resistance of this wire and find it to be R = 156 Q. What is the resistivity of the material the wire is made out of? p= Problem 7: A particular wire has a length of L = 2.7 m and a circular cross-sectional area of radius r= 1.69 mm. G= sin() cos cotan() asin()) acotan() atan() cosh() tanh() I= sin()) cos() cotan() asin() sinh() atan() acotan cosh() tanh() cotanh() Degrees O Radians B Degrees O Radians Part (b) What is the conductivity of this wire, in inverse Ohms per meter? 0 tan()) π ( acos() E ^^^L sinh() cotanh() g L P Y d h m r tan() π acos() E ^^^^ π E 1 Part (c) Give an expression for the current density in the wire if an electric field E is passing through it. Write this in terms of the resistivity and the other variables in the problem. J= n R ( ^^^ sin() cos() cotan() asin() atan() acotan() cosh() + + 7 8 9 4 5 6 1 2 3 0 END NO BACKSPACE DEL CLEAR Part (d) Calculate the current in the wire, in milliamperes, if the field strength is 5.28 V/m. - END NO…A heating element is made by maintaining a potential difference of 75.0 V across the length of a Nichrome wire has a 2.60 x 10-6 m² cross section. Nichrome has a resistiv of 5.00 x 10-7 m. If the element dissipates 5000 W, wha its length? Give your answer in cm.