Consider a parallel plate capacitor. The space between the plates is filled with two slabs of linear dielectric material. Each slab has the thickness d/2, so that the distance between the plates is d. K1 K2 The dielectric constant of slab at the top is 2, the dielectric constant of slab at the bottom is 1.5. The free charge density on the top plate is +o, and at the bottom plate -o. Find the bound charge density

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**Displacement Field Analysis**

In the previous question, how large (magnitude) is the displacement field?

1. **In the Top Slab**
   - **Magnitude \( D_{\text{top}} \) =** [Input required]
   - **Direction**: In which direction does it point? (up/down) [Input required]

2. **In the Bottom Slab**
   - **Magnitude \( D_{\text{bottom}} = \)** [Input required]
   - **Direction**: In which direction does it point? (up/down) [Input required]
Transcribed Image Text:**Displacement Field Analysis** In the previous question, how large (magnitude) is the displacement field? 1. **In the Top Slab** - **Magnitude \( D_{\text{top}} \) =** [Input required] - **Direction**: In which direction does it point? (up/down) [Input required] 2. **In the Bottom Slab** - **Magnitude \( D_{\text{bottom}} = \)** [Input required] - **Direction**: In which direction does it point? (up/down) [Input required]
**Parallel Plate Capacitor with Dielectric Slabs**

Consider a parallel plate capacitor. The space between the plates is filled with two slabs of linear dielectric material. Each slab has a thickness of \(d/2\), making the total distance between the plates \(d\).

**Diagram Description:**

The diagram shows a side view of a parallel plate capacitor. Two dielectric slabs are positioned between the plates. The slab on the top is labeled \(K_1\) and the slab on the bottom is labeled \(K_2\). Each slab is of equal thickness, \(d/2\).

**Dielectric Constants:**

- The dielectric constant of the slab at the top (\(K_1\)) is 2.
- The dielectric constant of the slab at the bottom (\(K_2\)) is 1.5.

**Charge Density:**

- The free charge density on the top plate is \(+\sigma\).
- The free charge density on the bottom plate is \(-\sigma\).

**Task:**

Find the bound charge density at the following locations:

- At the bottom of the lower slab
- At the bottom of the upper slab
- At the top of the lower slab
- At the top of the upper slab

**Instructions:**

Write \(\sigma\) as "sigma" and use a slash "/" for division. Remember to indicate the sign of the charge density ("+" or "-").
Transcribed Image Text:**Parallel Plate Capacitor with Dielectric Slabs** Consider a parallel plate capacitor. The space between the plates is filled with two slabs of linear dielectric material. Each slab has a thickness of \(d/2\), making the total distance between the plates \(d\). **Diagram Description:** The diagram shows a side view of a parallel plate capacitor. Two dielectric slabs are positioned between the plates. The slab on the top is labeled \(K_1\) and the slab on the bottom is labeled \(K_2\). Each slab is of equal thickness, \(d/2\). **Dielectric Constants:** - The dielectric constant of the slab at the top (\(K_1\)) is 2. - The dielectric constant of the slab at the bottom (\(K_2\)) is 1.5. **Charge Density:** - The free charge density on the top plate is \(+\sigma\). - The free charge density on the bottom plate is \(-\sigma\). **Task:** Find the bound charge density at the following locations: - At the bottom of the lower slab - At the bottom of the upper slab - At the top of the lower slab - At the top of the upper slab **Instructions:** Write \(\sigma\) as "sigma" and use a slash "/" for division. Remember to indicate the sign of the charge density ("+" or "-").
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