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Consider a mixture of the following molecules. Which molecule will be in the organic layer after treatment with excess acid (e.g. HCI)? O HO A A B C D NH₂ None of the above B NH₂ C NH₂ D

Consider a mixture of the following molecules. Which molecule will be in the organic layer after treatment with excess acid (e.g. HCI)? O HO A A B C D NH₂ None of the above B NH₂ C NH₂ D

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Consider a mixture of the following molecules. Which molecule will be in the organic layer after treatment with excess acid (e.g. HCI)? NH₂ HO A A B C D NH₂ None of the above NH₂ D
Transcribed Image Text:Consider a mixture of the following molecules. Which molecule will be in the organic layer after treatment with excess acid (e.g. HCI)? NH₂ HO A A B C D NH₂ None of the above NH₂ D
You decided the make the following changes to the Recrystallization experiment. Otherwise, the reaction was performed as written in the Recrystallization lab manual. You use: 1.3 g of p-aminophenol (MW-109.13 g/mol) 1.0 mL of 12 M HCI (MW=36.5 g/mol, density=1.18 g/mL) 0.91 mL of pure acetic anhydride (MW=102.09 g/mol, density=1.08 g/mL) If you isolate 0.89 g of pure tylenol (MW=151.165 g/mol), what is the % yield of the reaction? Please answer in % form as a whole number (no decimal places). You DO NOT need to include the % sign in your answer.
Transcribed Image Text:You decided the make the following changes to the Recrystallization experiment. Otherwise, the reaction was performed as written in the Recrystallization lab manual. You use: 1.3 g of p-aminophenol (MW-109.13 g/mol) 1.0 mL of 12 M HCI (MW=36.5 g/mol, density=1.18 g/mL) 0.91 mL of pure acetic anhydride (MW=102.09 g/mol, density=1.08 g/mL) If you isolate 0.89 g of pure tylenol (MW=151.165 g/mol), what is the % yield of the reaction? Please answer in % form as a whole number (no decimal places). You DO NOT need to include the % sign in your answer.
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