Consider a double-fluid manometer attached to an air pipe shown in Figure below. If the specific gravity of one fluid SG, is 13.55, and its height h is 22 c m 1. Determine the specific gravity of the other fluid for 76 kPa absolute pressure of air. Take the atmospheric pressure to be 100 kP a 2. Would the indicated air pressure be different for the given heights, if the used manometer was closed end type? Explai 3. Determine the height of a mercury column that would create the same Air pressure mentioned in point 1 Air %3D 33 cm SG, h1 cm SG, = 13.55
Consider a double-fluid manometer attached to an air pipe shown in Figure below. If the specific gravity of one fluid SG, is 13.55, and its height h is 22 c m 1. Determine the specific gravity of the other fluid for 76 kPa absolute pressure of air. Take the atmospheric pressure to be 100 kP a 2. Would the indicated air pressure be different for the given heights, if the used manometer was closed end type? Explai 3. Determine the height of a mercury column that would create the same Air pressure mentioned in point 1 Air %3D 33 cm SG, h1 cm SG, = 13.55
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:Consider a double-fluid manometer attached to an air pipe shown in Figure below. If the specific gravity of one fluid SG, is 13.55, and its height h, is 22 c
m
1. Determine the specific gravity of the other fluid for 76 kPa absolute pressure of air. Take the atmospheric pressure to be 100 kP
a
2. Would the indicated air pressure be different for the given heights, if the used manometer was closed end type? Explai
n
3. Determine the height of a mercury column that would create the same Air pressure mentioned in point 1
Air
P =
33 ст
SG,
hi cm
SG, = 13.55
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