Consider a dataset is normally distributed with a standard deviation of 8. Suppose the test scoresfrom a sample size of 20 students in a class has a sample mean of 72.Is sigma known for this problem? [Select]What is Maximal Margin of Error (E) at 90% confidence? [Select]Construct a 90% confidence interval. [Select]+

normal distributionσ = 8n = 20x¯ = 72

Answered: Consider a dataset is normally…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a study on running and happiness, runners indicated the number of miles they ran in a day and their subsequent score on a Happiness Survey (higher score = greater happiness). Runner # of miles (x) Happiness Score (y) 1 16 12 2 4 3 12 14 4 2 8 For these data: The mean of miles run is: 8.50 The mean of the Happiness scores is: 10.00 The standard deviation of the Miles scores is: 5.72 The standard deviation of the Happiness scores is: 3.16 In your submission, please include a copy of the SPSS or Excel output and answer the following: A. What is the r and r? value? B. Based on Pearson's r and r2 value, describe the relationship (direction/strength) that exists between # of miles run and Happiness scores. C. Create a scatterplot for the data using Excel or SPSS (include output in your submission). D. Insert the prediction line from Excel/SPSS on your scatterplot.
A sample of 20 bags of mulch had a mean weight of 52 pounds with a standard deviation of 3.8 pounds. Find the 95% confidence interval of the true mean. Show all your work for or explain how you obtained your answer in the space provided below.
The mean score on a driving exam for a group of driver’s education students is 76 points, with a standard deviation of 6 points. Apply chebychev’s theorem to the data using K=2. Interpret, At least ___% of the exam score falls between ___and ____
## In a survey of adults with diabetes, the average body mass index (BMI) in a sample of 1938 women was 32.2 with a standard deviation of 0.03. The BMI in a sample of 1555 men was 30.4, with a standard deviation of 0.06. Construct a 92% confidence interval for the difference in the mean BMI between women and men with diabetes, INTERPRET THE RESULTS. DOES THE CONFIDENCE INTERVAL CONTRADICT THE CLAIM THAT THE MEAN BMI IS THE SAME FOR BOTH MEN AND WOMEN WITH DIABETES?
The combined SAT scores for the students at a local high school are normally distributed with a mean of 1479 and a standard deviation of 310. The local college includes a minimum score of 642 in its admission requirements.What percentage of students from this school earn scores that fail to satisfy the admission requirement?P(X < 642) = %
You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 20 night students, and the sample mean GPA is 2.94 with a standard deviation of 0.8. You sample 55 day students, and the sample mean GPA is 2.56 with a standard deviation of 0.44. Test the claim using a 1% level of significance. Assume the population standard deviations are unequal and that GPAs are normally distributed. What are the correct hypotheses? Based on the hypotheses, find the following:Test Statistic = Critical Values = ±
A researcher is interested in finding a 95% confidence interval for the mean number minutes students are concentrating on their professor during a one hour statistics lecture. The study included 133 students who averaged 36.1 minutes concentrating on their professor during the hour lecture. The standard deviation was 13.4 minutes. Round answers to 3 decimal places where possible. b. With 95% confidence the population mean minutes of concentration is between and minutes. c. If many groups of 133 randomly selected members are studied, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean minutes of concentration and about percent will not contain the true population mean minutes of concentration.
You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 30 night students, and the sample mean GPA is 2.83 with a standard deviation of 0.94. You sample 55 day students, and the sample mean GPA is 2.97 with a standard deviation of 0.92. Test the claim using a 1% level of significance. Assume the population standard deviations are unequal and that GPAs are normally distributed. Give answer to at least 4 decimal places. What are the correct hypotheses?H0: Select an answer μ σ² μ₂ p μ₁ x̄₂ s² x̄₁ = Select an answer μ x̄₂ σ² μ₂ x̄₁ μ₁ s² p H1: Select an answer σ² μ x̄₁ s² p x̄₂ μ₁ μ₂ ? = < > ≤ ≠ ≥ Select an answer μ x̄₂ x̄₁ μ₂ σ² s² μ₁ p Based on the hypotheses, find the following:Test Statistic = Critical Values = ±± (Just enter the positive CV.)The correct decision is to Select an answer Reject the null hypothesis Fail to reject the null hypothesis The correct summary would be: Select an answer There is not enough…
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A math teacher claims that she has developed a review course that increases the scores of students on the math portion of a college entrance exam. Based on data from the administrator of the exam, scores are normally distributed with μ = 514. The teacher obtains a random sample of 1800 students, puts them through the review class, and finds that the mean math score of the 1800 students is 520 with a standard deviation of 112. Complete parts (a) through (d) below. to = 1.04 (Round to two decimal places as needed.) Find the P-value. The P-value is (Round to three decimal places as needed.)
I have a question: You are interested in estimating the the mean weight of the local adult population of female white-tailed deer (doe). From past data, you estimate that the standard deviation of all adult female white-tailed deer in this region to be 21 pounds. What sample size would you need to in order to estimate the mean weight of all female white-tailed deer, with a 94% confidence level, to within 4 pounds of the actual weight?

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