Consider a data set containing the following values: 80, 94, 93, 106, 91, 90, 96, 99 The mean of the preceding values is 93.625. The deviations from the mean have been calculated as follows: -13.625, 0.375, -0.625, 12.375, -2.625, -3.625, 2.375, 5.375 If this is sample data, what is the sample variance? What is the sample standard deviation? If this is population data, what is the population variance? What is the population standard deviation? Suppose the largest value of 106 in the data was misrecorded as 100. If you were to recalculate the variance and standard deviation with the 100 instead of the 106, your new values for the variance and standard deviation would be...
Consider a data set containing the following values: 80, 94, 93, 106, 91, 90, 96, 99 The mean of the preceding values is 93.625. The deviations from the mean have been calculated as follows: -13.625, 0.375, -0.625, 12.375, -2.625, -3.625, 2.375, 5.375 If this is sample data, what is the sample variance? What is the sample standard deviation? If this is population data, what is the population variance? What is the population standard deviation? Suppose the largest value of 106 in the data was misrecorded as 100. If you were to recalculate the variance and standard deviation with the 100 instead of the 106, your new values for the variance and standard deviation would be...
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 11PPS
Related questions
Question
Consider a data set containing the following values:
80, 94, 93, 106, 91, 90, 96, 99
The mean of the preceding values is 93.625. The deviations from the mean have been calculated as follows:
-13.625, 0.375, -0.625, 12.375, -2.625, -3.625, 2.375, 5.375
If this is sample data, what is the sample variance?
What is the sample standard deviation?
If this is population data, what is the population variance?
What is the population standard deviation?
Suppose the largest value of 106 in the data was misrecorded as 100. If you were to recalculate the variance and standard deviation with the 100 instead of the 106, your new values for the variance and standard deviation would be...
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