The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance, and standard deviation population data set. 2, 9, 15, 4, 15, 6, 12, 8, 5,9 The range is 13. (Simplify your answer.) The population mean is 8.5. (Simplify your answer. Round to the nearest tenth as needed.) The population variance is (Simplify your answer. Round to the nearest tenth as needed.)
The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance, and standard deviation population data set. 2, 9, 15, 4, 15, 6, 12, 8, 5,9 The range is 13. (Simplify your answer.) The population mean is 8.5. (Simplify your answer. Round to the nearest tenth as needed.) The population variance is (Simplify your answer. Round to the nearest tenth as needed.)
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![### Statistics for Football Team Wins
The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance, and standard deviation of the population data set.
**Data Set:**
\[ 2, 9, 15, 4, 15, 6, 12, 8, 5, 9 \]
#### Calculations
1. **Range:**
The range is calculated as the difference between the maximum and minimum values in the data set.
\[
\text{Range} = \text{max} - \text{min} = 15 - 2 = 13
\]
**The range is** \( \boxed{13} \).
2. **Population Mean:**
The mean is the average of the data set, calculated by summing all the values and dividing by the number of values.
\[
\text{Mean} = \frac{2 + 9 + 15 + 4 + 15 + 6 + 12 + 8 + 5 + 9}{10} = \frac{85}{10} = 8.5
\]
**The population mean is** \( \boxed{8.5} \) (simplify your answer. Round to the nearest tenth as needed).
3. **Population Variance:**
The variance measures the spread of the numbers in the data set. It is calculated by finding the average of the squared differences from the mean.
\[
\begin{align*}
\text{Variance} &= \frac{\sum_{i=1}^N (x_i - \mu)^2}{N} \\
&= \frac{(2-8.5)^2 + (9-8.5)^2 + (15-8.5)^2 + (4-8.5)^2 + (15-8.5)^2 + (6-8.5)^2 + (12-8.5)^2 + (8-8.5)^2 + (5-8.5)^2 + (9-8.5)^2}{10}
\end{align*}
\]
Calculating each squared difference:
\[
\begin{align*}
(2 - 8.5)^2 &= 42.25](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe5ff9c3f-9717-4427-81ca-9eaa3fb6edc8%2F17848839-1c59-461f-bc9b-3d09464b7e32%2Fhigjtwjo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Statistics for Football Team Wins
The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance, and standard deviation of the population data set.
**Data Set:**
\[ 2, 9, 15, 4, 15, 6, 12, 8, 5, 9 \]
#### Calculations
1. **Range:**
The range is calculated as the difference between the maximum and minimum values in the data set.
\[
\text{Range} = \text{max} - \text{min} = 15 - 2 = 13
\]
**The range is** \( \boxed{13} \).
2. **Population Mean:**
The mean is the average of the data set, calculated by summing all the values and dividing by the number of values.
\[
\text{Mean} = \frac{2 + 9 + 15 + 4 + 15 + 6 + 12 + 8 + 5 + 9}{10} = \frac{85}{10} = 8.5
\]
**The population mean is** \( \boxed{8.5} \) (simplify your answer. Round to the nearest tenth as needed).
3. **Population Variance:**
The variance measures the spread of the numbers in the data set. It is calculated by finding the average of the squared differences from the mean.
\[
\begin{align*}
\text{Variance} &= \frac{\sum_{i=1}^N (x_i - \mu)^2}{N} \\
&= \frac{(2-8.5)^2 + (9-8.5)^2 + (15-8.5)^2 + (4-8.5)^2 + (15-8.5)^2 + (6-8.5)^2 + (12-8.5)^2 + (8-8.5)^2 + (5-8.5)^2 + (9-8.5)^2}{10}
\end{align*}
\]
Calculating each squared difference:
\[
\begin{align*}
(2 - 8.5)^2 &= 42.25
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