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Consider a conical pendulum with a bob of mass m = 80kg on a string of length L = 10m that makes an angle of 0 = 50 with the vertical. Determine (a) the horizontal and vertical components of the force exerted by the string on the pendulum and (b) the radial acceleration of the bob. EF, =T cos0 – mg = 0 | mg (80.0kg)(9.80 m/s²) 5.00 T = cos e T=Tsinei+T cosej = 787 N %3D cos 5.00° = (68.6 N)î+(784 N)ĵ SF, =T sin0 = ma. mg T sin0 (787 N)sin 5.00° 0 857 m /s? 11

Consider a conical pendulum with a bob of mass m = 80kg on a string of length L = 10m that makes an angle of 0 = 50 with the vertical. Determine (a) the horizontal and vertical components of the force exerted by the string on the pendulum and (b) the radial acceleration of the bob. EF, =T cos0 – mg = 0 | mg (80.0kg)(9.80 m/s²) 5.00 T = cos e T=Tsinei+T cosej = 787 N %3D cos 5.00° = (68.6 N)î+(784 N)ĵ SF, =T sin0 = ma. mg T sin0 (787 N)sin 5.00° 0 857 m /s? 11

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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why is that equation set to 0 and the other set to ma?

Consider a conical pendulum with a bob of mass m = 80kg on a string of length L = 10m that makes an angle of 0 = 50 with the vertical. Determine (a) the horizontal and vertical components of the force exerted by the string on the pendulum and (b) %3D the radial acceleration of the bob. EF, =T cos0– mg = 0 || mg (80.0 kg)(9.80 m/s²) 5.00° = 787 N T = cos e T=Tsineî +T cosej cos 5.00° = (68.6 N)î+(784 N)¡ SF =T sin0 = ma. mg T sine (787 N)sin 5.00° a. 0.857 m/s? 11 80.0 kg
Transcribed Image Text:Consider a conical pendulum with a bob of mass m = 80kg on a string of length L = 10m that makes an angle of 0 = 50 with the vertical. Determine (a) the horizontal and vertical components of the force exerted by the string on the pendulum and (b) %3D the radial acceleration of the bob. EF, =T cos0– mg = 0 || mg (80.0 kg)(9.80 m/s²) 5.00° = 787 N T = cos e T=Tsineî +T cosej cos 5.00° = (68.6 N)î+(784 N)¡ SF =T sin0 = ma. mg T sine (787 N)sin 5.00° a. 0.857 m/s? 11 80.0 kg
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