Consider a collision between two particles in which their masses m, and m, are unchanged. Use conservation of momentum, conservation of energy and Newton's law of impact to show that the energy Q released by the collision is Q = (1 – e²)+µ(u, – u,)² , (1) where u, and u, are the initial velocities and m,m2 (2) = 11 (т, + m,)
Consider a collision between two particles in which their masses m, and m, are unchanged. Use conservation of momentum, conservation of energy and Newton's law of impact to show that the energy Q released by the collision is Q = (1 – e²)+µ(u, – u,)² , (1) where u, and u, are the initial velocities and m,m2 (2) = 11 (т, + m,)
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Transcribed Image Text:Consider a collision between two particles in which their masses m, and m, are
unchanged. Use conservation of momentum, conservation of energy and Newton's law
of impact to show that the energy Q released by the collision is
Q = (1 – e?)+µ(u, – u,)² ,
(1)
where u, and u, are the initial velocities and
m,m2
(2)
= 11
(т, + m,)
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