Consider a circuit with three capacitors connected in series. The capacitances are C₁ = 2.3 μF, C₂ = 1.8 μF, and C₂ = 5.1 μF. What is the equivalent capacitance (in µF) of the three capacitors? 0.811 x 1 Cea x Are the capacitors connected in series or parallel? Remember that for capacitors in series, - C₁ = 2.3 μF If a 17.0 V potential is applied to the circuit, what is the charge (in uC) of each capacitor? 14.33 ✓ Correct. We know the equivalent capacitance from the previous question. We also know that the charges on capacitors connected in series are the same. Thus, we can multiple the equivalent capacitance by the applied potential to determine the charge. μC If we now connect C₁ in series to C₂ and C in parallel, what is the equivalent capacitance (in µF)? (Note: C₁ = 2.3 µF, C₂ = 1.8 µF, and C = 5.1 µF.) C₂ = 1.8 μF C3 = 5.1 μF Ⓡ 0.677 x x Are the capacitors connected in series or parallel? Remember that for capacitors in series, -Σ. TC₁ Ceg while in parallel: Ceq=C, HF = LC₁ while in parallel: C- CHF

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Consider a circuit with three capacitors connected in series. The capacitances are C₁ = 2.3 μF, C₂ = 1.8 μF, and C3 = 5.1 µF. What is the equivalent capacitance (in µF) of the three capacitors?
0.811
X
x Are the capacitors connected in series or parallel? Remember that for capacitors in series,
0.677
C₁ = 2.3 μF
1
C3 = 5.1 μF
eq
=
If a 17.0 V potential is applied to the circuit, what is the charge (in µC) of each capacitor?
14.33
✓ Correct. We know the equivalent capacitance from the previous question. We also know that the charges on capacitors connected in series are the same. Thus, we can multiple the equivalent capacitance by the
applied potential to determine the charge. µC
If we now connect C₁ in series to C₂ and C3 in parallel, what is the equivalent capacitance (in µF)? (Note: C₁ = 2.3 µF, C₂ = 1.8 µF, and C3 = 5.1 µF.)
C₂ = 1.8 μF
1
Ceq
1
¡C;
while in parallel: Ceq
=
=
ΣC, UF
X
x Are the capacitors connected in series or parallel? Remember that for capacitors in series, -¹ while in parallel: Ce
Σε
eqa = [c₁
eg
HF
Transcribed Image Text:Consider a circuit with three capacitors connected in series. The capacitances are C₁ = 2.3 μF, C₂ = 1.8 μF, and C3 = 5.1 µF. What is the equivalent capacitance (in µF) of the three capacitors? 0.811 X x Are the capacitors connected in series or parallel? Remember that for capacitors in series, 0.677 C₁ = 2.3 μF 1 C3 = 5.1 μF eq = If a 17.0 V potential is applied to the circuit, what is the charge (in µC) of each capacitor? 14.33 ✓ Correct. We know the equivalent capacitance from the previous question. We also know that the charges on capacitors connected in series are the same. Thus, we can multiple the equivalent capacitance by the applied potential to determine the charge. µC If we now connect C₁ in series to C₂ and C3 in parallel, what is the equivalent capacitance (in µF)? (Note: C₁ = 2.3 µF, C₂ = 1.8 µF, and C3 = 5.1 µF.) C₂ = 1.8 μF 1 Ceq 1 ¡C; while in parallel: Ceq = = ΣC, UF X x Are the capacitors connected in series or parallel? Remember that for capacitors in series, -¹ while in parallel: Ce Σε eqa = [c₁ eg HF
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