Consider a chemical reaction that has a AH°f = 30.0 kJ/mol and a AS° = 100.0 J//mol•K). At what temperature does this reaction become spontaneous? 2.00 x 102 K 3.00 х 103 к 1.30 х 10? к 7.00 x 101 K 3.00 x 102 K
Consider a chemical reaction that has a AH°f = 30.0 kJ/mol and a AS° = 100.0 J//mol•K). At what temperature does this reaction become spontaneous? 2.00 x 102 K 3.00 х 103 к 1.30 х 10? к 7.00 x 101 K 3.00 x 102 K
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
Consider a chemical reaction that has a ΔH° = 30.0 kJ/mol and a ΔS° = 100.0 J/(mol•K). At what temperature does this reaction become spontaneous?
**Options:**
- ○ 2.00 x 10² K
- ○ 3.00 x 10³ K
- ○ 1.30 x 10² K
- ○ 7.00 x 10¹ K
- ○ 3.00 x 10² K
**Explanation:**
To determine the temperature at which the reaction becomes spontaneous, you will use the Gibbs free energy equation:
\[ \Delta G = \Delta H - T \Delta S \]
A reaction is spontaneous when \(\Delta G < 0\).
Given:
- \(\Delta H° = 30.0 \text{ kJ/mol} = 30000 \text{ J/mol}\)
- \(\Delta S° = 100.0 \text{ J/(mol•K)}\)
Set the equation to zero and solve for \(T\):
\[ 0 = 30000 - T \times 100 \]
\[ T = \frac{30000}{100} = 300 \text{ K} \]
Thus, the temperature at which the reaction becomes spontaneous is 300 K.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fec3b779b-d0d6-4768-9dcd-21f6961c75e0%2F21383d57-2a3d-4653-b4f7-2fb7ca101add%2F1k3fq0n_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Consider a chemical reaction that has a ΔH° = 30.0 kJ/mol and a ΔS° = 100.0 J/(mol•K). At what temperature does this reaction become spontaneous?
**Options:**
- ○ 2.00 x 10² K
- ○ 3.00 x 10³ K
- ○ 1.30 x 10² K
- ○ 7.00 x 10¹ K
- ○ 3.00 x 10² K
**Explanation:**
To determine the temperature at which the reaction becomes spontaneous, you will use the Gibbs free energy equation:
\[ \Delta G = \Delta H - T \Delta S \]
A reaction is spontaneous when \(\Delta G < 0\).
Given:
- \(\Delta H° = 30.0 \text{ kJ/mol} = 30000 \text{ J/mol}\)
- \(\Delta S° = 100.0 \text{ J/(mol•K)}\)
Set the equation to zero and solve for \(T\):
\[ 0 = 30000 - T \times 100 \]
\[ T = \frac{30000}{100} = 300 \text{ K} \]
Thus, the temperature at which the reaction becomes spontaneous is 300 K.
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