Consider a car repair factory. The number of customers who arrive for repairs follows a Poisson distribution, about 4 customers per hour on average. Repair time follows a Negative Exponential distribution, each service takes an average of 10 minutes. a) What is the average number of customers in the factory? b) What is the average time each customer spent in the factory (in minutes)? Oa) 2: b) 30 O a) 1.33; b) 20 O a) 1.33; b) 30 Oa) 2; b) 20

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Consider a car repair factory. The number of customers who arrive for repairs follows a Poisson distribution, about 4 customers per hour on average. Repair
time follows a Negative Exponential distribution, each service takes an average of 10 minutes.
a) What is the average number of customers in the factory?
b) What is the average time each customer spent in the factory (in minutes)?
O a) 2; b) 30
O a) 1.33; b) 20
O a) 1.33; b) 30
Oa) 2; b) 20
Transcribed Image Text:Consider a car repair factory. The number of customers who arrive for repairs follows a Poisson distribution, about 4 customers per hour on average. Repair time follows a Negative Exponential distribution, each service takes an average of 10 minutes. a) What is the average number of customers in the factory? b) What is the average time each customer spent in the factory (in minutes)? O a) 2; b) 30 O a) 1.33; b) 20 O a) 1.33; b) 30 Oa) 2; b) 20
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