Consider a binary mixture of species a and b that results in two coexisting liquids (a and ß) at 298.15 K and 1 bar. The mixture is well-described by a one-constant (also known as two-suffix) Margules equation ex 9 RT = 3.127xaxb The ideal-gas constant R = 8.3145 J/(mol K) Obtain general expressions for both species a and b that define the conditions for phase equilibrium. The expressions can contain constants, temperature, pressure, and compositions. (Note: If you do not obtain a result for this part and need one for subsequent parts, please use (x)² = 0.73244 exp(Ar) x = 0.003786 exp(A(x)²)

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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Consider a binary mixture of species a and b that results in two coexisting liquids (a and ß) at 298.15 K and 1 bar.
The mixture is well-described by a one-constant (also known as two-suffix) Margules equation
ex
9
RT
= 3.127xaxb
The ideal-gas constant R = 8.3145 J/(mol K)
Obtain general expressions for both species a and b that define the conditions for phase equilibrium.
The expressions can contain constants, temperature, pressure, and compositions.
(Note: If you do not obtain a result for this part and need one for subsequent parts, please use
(x)² = 0.73244 exp(Ax²)
x=0.003786 exp(A(x)²)
Transcribed Image Text:Consider a binary mixture of species a and b that results in two coexisting liquids (a and ß) at 298.15 K and 1 bar. The mixture is well-described by a one-constant (also known as two-suffix) Margules equation ex 9 RT = 3.127xaxb The ideal-gas constant R = 8.3145 J/(mol K) Obtain general expressions for both species a and b that define the conditions for phase equilibrium. The expressions can contain constants, temperature, pressure, and compositions. (Note: If you do not obtain a result for this part and need one for subsequent parts, please use (x)² = 0.73244 exp(Ax²) x=0.003786 exp(A(x)²)
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