Consider a A = 16.0000 m² wall with two layers of insulation: d = 16 cm of brick wall and d = 12 cm of styrofoam. Temperature outside is Tout = 3 °C and Tw = 10 °C between styrofoam and brick layers. Heat flow through the wall is measured for t = 10 h

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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What is the amount of heat passed through the wall?
Q = 201*10^5
J
Your last answer was interpreted as follows: 201. 105
What is the inside temperature?
Tin =|170*10^-
°C
Your last answer was interpreted as follows: 170. 10-¹
Do not leave any fields blank. If you don't know the answer, insert 1 for example.
Transcribed Image Text:What is the amount of heat passed through the wall? Q = 201*10^5 J Your last answer was interpreted as follows: 201. 105 What is the inside temperature? Tin =|170*10^- °C Your last answer was interpreted as follows: 170. 10-¹ Do not leave any fields blank. If you don't know the answer, insert 1 for example.
Consider a A = 16.0000 m² wall with two layers of insulation: d = 16 cm of brick wall and de = 12 cm of styrofoam. Temperature outside is
Tout = 3 °C and Tw= 10 °C between styrofoam and brick layers. Heat flow through the wall is measured for t = 10 h
d₂ = 12 cm
d = 16 cm
Outside
Tout = 3 °C
foam
T₁ = 10 °C
K = 0.8 W/(mK)
A 16.0 m²
K = 0.01 W/(mK
Inside
Tin
m²
Ø
system of coordinates
What is the heat flow through the wall divided by wall area?
$= 350*10^-1
W
=
Your last answer was interpreted as follows: 350 - 10-¹
What is the heat flow (power) through the wall?
P = 560*10^O
W
Transcribed Image Text:Consider a A = 16.0000 m² wall with two layers of insulation: d = 16 cm of brick wall and de = 12 cm of styrofoam. Temperature outside is Tout = 3 °C and Tw= 10 °C between styrofoam and brick layers. Heat flow through the wall is measured for t = 10 h d₂ = 12 cm d = 16 cm Outside Tout = 3 °C foam T₁ = 10 °C K = 0.8 W/(mK) A 16.0 m² K = 0.01 W/(mK Inside Tin m² Ø system of coordinates What is the heat flow through the wall divided by wall area? $= 350*10^-1 W = Your last answer was interpreted as follows: 350 - 10-¹ What is the heat flow (power) through the wall? P = 560*10^O W
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