Consider a 10 nC charge located at the origin, what will be Ele resent the Electrical field in Cartesian coordinates.
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- Imagine a right angle triangle with two equal sides of 10 cm Two equal charges of +10µC are placed in the vertices corresponding to the 450 angles A negative, -20uC charge is placed at the 90° vertex Find the electnc field in the middle of the hypotenuse. You need to provide the magnitude of the field and the direction. For the direction use the angle between the electric field and the hypotenuse (the one less than 90°) Part A - What is the magnitude of the field at the point in the midle of the hypothenuse? Value Units Submit Request Answer Part B. What is the angle between the total field and the hypothenuse? Give the angle which less than 90 degrees.(a) Calculate the strength and direction of the electric field, E, due to point charge of 1.8 nC at a distance 4.4 mm from the charge. For the direction, consider the line joining the point charge and point at the distance 4.4 mm. The direction on this line away from the charge is positive and the direction towards the charge is negative. E = (b) What force does the electric field found in the previous example exert on a point charge of −2.5·10−8 C? Hint: Indicate a force pointing in the direction of the field as positive and opposite the field as negative. F= NHow to solve this question
- A +2.0 nCnC charge is at the origin and a -5.0 nCnCcharge is at xx = 1.4 cmcm. At what xx-coordinate could you place a proton so that it would experience no net force?A 4-nC charged arc have radius of 2 m and arc angle of 60 degree. Find the electric field at the arc circular center. Now if the arc is straighted into rod of length 6 m, what will the electric field at that point (the distance from the center of the rod is still the radius) be?A charge particle moving at vo enters the region between two parallel plates with charge densities of magnitude o (Figure). Calculate (a) the magnitude of the electric field E between the plates, (b) the magnitude of the electric force F. acting on the charged particle, and (c) the acceleration a of the particle. (d) Find the y-displacement 4y of the charged particle when it reaches the far edge of the plates, a horizontal distance d from where it entered. Assume that the charged particle does not hit either of the plates, and that upward is positive y-direction. E F. 4y Charge #: particle Vo a m/s nC/m? cm N/C m/s? m 10 electron 2.50x10 3.50 2.00 ++ + d- X= 0
- llege of Science First year Dr. Munther 3. A point charge of +3.00 x 10-6 C is 12.0 cm distant from a second point charge of -1.50 x 10-6 C. Calculate the magnitude of the force on each charge. Being of opposite signs, the two charges attract one anot her, and the magnitude of this force is given by Coulomb's law (Eq. 1.3),Two objects are identical and small enough that their sizes canbe ignored relative to the distance between them, which is 0.183 m.In a vacuum, each object carries a different charge, and theyattract each other with a force of 1.05 N. The objects are broughtinto contact, so the net charge is shared equally, and then theyare returned to their initial positions. Now it is found that theobjects repel one another with a force whose magnitude is equal tothat of the initial attractive force. What is the initial charge oneach object, the answer to part (a) being the onewith the greater (and positive) value? (a) (b) Number Number Units UnitsA ring of charge is centered at the origin in the vertical direction. The ring has a charge density of a = 6.93 × 10-6 C/m and a radius of R = 2.15 cm. dq Find the total electric field, E, of the ring at the point P = (1.56 m, 0.00 m). The Coulomb force constant is k = 1/(4xe0) = 8.99 × 10º N-m²/C². R dE E = N/C Find the expression for the electric field, E», of the ring as the point P becomes very far from the ring (x > R) in terms of the radius R, the distance x, the total charge on the ring q, and the constant k = 1/(4ле). E = P.
- AQ B 47 Exo 10 kle consider a distribution Consisting of 3 puent charges. Is, 72 $ 78 placed on an axis of respectively at pounts A, B and O where pount O is the midpoint of the segment AB of length 2a. We give 71 - 92 = 0 70 and 73 = -20 a) Let p be a point on the Ox ares with positive. abscissa X. Determine the expression of the electrostatic fueld & CP) created at point & by the p distribution of pount charges. B) Determine the expression of the electrostatic. potential (p) created at? distribution of pount charges. pount P by theThree charges are positioned at the corners of aparallelogram as shown below. (a) If Q = 8.0 µC, what isthe electric field at the unoccupied corner? (b) What is theforce on a 5.0-µC charge placed at this corner?What is the angle between the electrostatic force on the charge at the origin and the pos- itive z-axis? Answer in degrees as an angle between -180° and 180° measured from the positive x-axis, with counterclockwise posi- tive. Answer in units of °.