Consider 1.00 mol of a monatomic ideal gas for which cv=3/2 R. The gas is subjected to a thermodynamic cycle composed of the following three steps: 1) Reduction of the pressure from 1.00 atm (A) to 0.100 atm (B). During this step, the volume remains constant at 10.0 L. 2) Isobaric expansion from a pressure of 0.100 atm and 10.O L (B) to a final volume of 100. L (C). 3) Isothermal compression from point C back to point A.
Consider 1.00 mol of a monatomic ideal gas for which cv=3/2 R. The gas is subjected to a thermodynamic cycle composed of the following three steps: 1) Reduction of the pressure from 1.00 atm (A) to 0.100 atm (B). During this step, the volume remains constant at 10.0 L. 2) Isobaric expansion from a pressure of 0.100 atm and 10.O L (B) to a final volume of 100. L (C). 3) Isothermal compression from point C back to point A.
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![Consider 1.00 mol of a monatomic ideal gas for which cv=3/2 R. The gas is
subjected to a thermodynamic cycle composed of the following three steps:
1) Reduction of the pressure from 1.00 atm (A) to 0.100 atm (B). During this step,
the volume remains constant at 10.0 L.
2) Isobaric expansion from a pressure of 0.100 atm and 10.0 L (B) to a final volume
of 100. L (C).
3) Isothermal compression from point C back to point A.
Thermodynamic Cycle
A
0.9
0.8
0.7
0.6
0.5
1
0.4
0.3
3
0.2
0.1
2
10
20
30
40
50
60
70
80
90
100
Volume (L)
What is the change in internal energy for the system in step 3?
a) -1370 J
b) 1370 J
c) OJ
d) -550 J
e) 912 J
Pressure (atm)
B.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6c22e4ce-c549-4263-bb0f-84b6f538ce83%2F4189e046-c19e-4e11-9f57-9eb34fd758fa%2F7014p7i_processed.png&w=3840&q=75)
Transcribed Image Text:Consider 1.00 mol of a monatomic ideal gas for which cv=3/2 R. The gas is
subjected to a thermodynamic cycle composed of the following three steps:
1) Reduction of the pressure from 1.00 atm (A) to 0.100 atm (B). During this step,
the volume remains constant at 10.0 L.
2) Isobaric expansion from a pressure of 0.100 atm and 10.0 L (B) to a final volume
of 100. L (C).
3) Isothermal compression from point C back to point A.
Thermodynamic Cycle
A
0.9
0.8
0.7
0.6
0.5
1
0.4
0.3
3
0.2
0.1
2
10
20
30
40
50
60
70
80
90
100
Volume (L)
What is the change in internal energy for the system in step 3?
a) -1370 J
b) 1370 J
c) OJ
d) -550 J
e) 912 J
Pressure (atm)
B.
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