(Conservative forces) Conservative forces have a very special property that we will explore in this problem. Consider a function U: R² → R which we will call the potential. The conservative force F associated to the potential U is given by (a) Consider the following potential F= -vu. 1 U(x, y) = x² + y²+1 Compute the force F associated to U and sketch the vector field associated to F. (You should produce something like Figure 2.18 from the lecture notes.) (b) Consider two curves C₁ and C₂ with injective parametrizations Y₁: (0,2л) → R² and Y2 (0,2π) R² given by 3 Y₁(t) = (0, Y2(t) = sin(t), 2π 2/7). Sketch the curves C₁ and C2. (c) Compute the curve integrals fc, F. ds and fc, F.ds. Do you notice anything? (d) If you've done things correctly, you should have found Sc, F. ds = Sc₂ F. ds: the answer is independent of the shape of the curve! In fact, you may have noticed that F. ds = F ds (u(0, 1) — U(0,0)) . C₁
(Conservative forces) Conservative forces have a very special property that we will explore in this problem. Consider a function U: R² → R which we will call the potential. The conservative force F associated to the potential U is given by (a) Consider the following potential F= -vu. 1 U(x, y) = x² + y²+1 Compute the force F associated to U and sketch the vector field associated to F. (You should produce something like Figure 2.18 from the lecture notes.) (b) Consider two curves C₁ and C₂ with injective parametrizations Y₁: (0,2л) → R² and Y2 (0,2π) R² given by 3 Y₁(t) = (0, Y2(t) = sin(t), 2π 2/7). Sketch the curves C₁ and C2. (c) Compute the curve integrals fc, F. ds and fc, F.ds. Do you notice anything? (d) If you've done things correctly, you should have found Sc, F. ds = Sc₂ F. ds: the answer is independent of the shape of the curve! In fact, you may have noticed that F. ds = F ds (u(0, 1) — U(0,0)) . C₁
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
part c) and d) please
![(Conservative forces) Conservative forces have a very special property that
we will explore in this problem. Consider a function U: R² → R which we will call the
potential. The conservative force F associated to the potential U is given by
(a) Consider the following potential
F= -vu.
1
U(x, y)
=
x² + y²+1
Compute the force F associated to U and sketch the vector field associated to F. (You
should produce something like Figure 2.18 from the lecture notes.)
(b) Consider two curves C₁ and C₂ with injective parametrizations Y₁: (0,2л) → R² and
Y2 (0,2π) R² given by
3
Y₁(t) = (0,
Y2(t) =
sin(t),
2π
2/7).
Sketch the curves C₁ and C2.
(c) Compute the curve integrals fc, F. ds and fc, F.ds. Do you notice anything?
(d) If you've done things correctly, you should have found Sc, F. ds = Sc₂ F. ds: the
answer is independent of the shape of the curve! In fact, you may have noticed that
F. ds = F ds (u(0, 1) — U(0,0)) .
C₁](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe8c5cbec-f2bb-49b4-94bb-4d6293937097%2F2166f22d-6296-48ba-9573-68cd5d278144%2F07g77oi_processed.png&w=3840&q=75)
Transcribed Image Text:(Conservative forces) Conservative forces have a very special property that
we will explore in this problem. Consider a function U: R² → R which we will call the
potential. The conservative force F associated to the potential U is given by
(a) Consider the following potential
F= -vu.
1
U(x, y)
=
x² + y²+1
Compute the force F associated to U and sketch the vector field associated to F. (You
should produce something like Figure 2.18 from the lecture notes.)
(b) Consider two curves C₁ and C₂ with injective parametrizations Y₁: (0,2л) → R² and
Y2 (0,2π) R² given by
3
Y₁(t) = (0,
Y2(t) =
sin(t),
2π
2/7).
Sketch the curves C₁ and C2.
(c) Compute the curve integrals fc, F. ds and fc, F.ds. Do you notice anything?
(d) If you've done things correctly, you should have found Sc, F. ds = Sc₂ F. ds: the
answer is independent of the shape of the curve! In fact, you may have noticed that
F. ds = F ds (u(0, 1) — U(0,0)) .
C₁
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