Confirm the following properties of the greatest common divisor: (a) If gcd(a , b) = 1, and gcd(a , c) = 1, then gcd(a , bc) = 1. [Hint: Because 1 = ax + by = au + cv for some x, y, u, v, 1 = (ax + by)(au + cv) = a(aux + cvx + byu) + bc(yv).] (b) If gcd(a , b) = 1, and c |a, then gcd(b , c) = 1. (c) If gcd(a , b) = 1, then gcd(ac , b) = gcd(c , b). %3D %3D %3D %3D

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Confirm the following properties of the greatest common divisor:
(a) If gcd(a , b) = 1, and gcd(a , c) = 1, then gcd(a , bc) = 1.
[Hint: Because 1 = ax + by = au + cv for some x, y, u, v,
(ax + by)(au + cv) = a(aux + cvx + byu) + bc(yv).]
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(b) If gcd(a , b) = 1, and c | a, then gcd(b , c) = 1.
(c) If gcd(a , b) = 1, then gcd(ac , b) = gcd(c , b).
(d) If gcd(a , b) = 1, and c | a + b, then gcd(a , c) = gcd(b , c) = 1.
[Hint: Let d = gcd(a , c). Then d | a, d | c implies that d | (a + b) – a
(e) If gcd(a , b) = 1, d | ac, and d |bc, then d | c.
(f) If gcd(a , b) = 1, then gcd(a² , b²) = 1.
[Hint: First show that ged(a , b²) = ged(a² , b) = 1.]
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Transcribed Image Text:Confirm the following properties of the greatest common divisor: (a) If gcd(a , b) = 1, and gcd(a , c) = 1, then gcd(a , bc) = 1. [Hint: Because 1 = ax + by = au + cv for some x, y, u, v, (ax + by)(au + cv) = a(aux + cvx + byu) + bc(yv).] %3D 1 %3D %3D (b) If gcd(a , b) = 1, and c | a, then gcd(b , c) = 1. (c) If gcd(a , b) = 1, then gcd(ac , b) = gcd(c , b). (d) If gcd(a , b) = 1, and c | a + b, then gcd(a , c) = gcd(b , c) = 1. [Hint: Let d = gcd(a , c). Then d | a, d | c implies that d | (a + b) – a (e) If gcd(a , b) = 1, d | ac, and d |bc, then d | c. (f) If gcd(a , b) = 1, then gcd(a² , b²) = 1. [Hint: First show that ged(a , b²) = ged(a² , b) = 1.] %3D %3D %3D %3D %3D %3D %3D
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