Find the left and right chi square values, then give the confidence interval.Sample Variance s = 14.6Confidence Level c = 0.90 and Sample Size n = 22LeftRight1+c1- cLevel of Significance aDegrees of Freedomn-1Confidence Interval for Variance o(n – 1)s²(n – 1)s?XRand XR%3D%3DAt the 90 % level of confidence the population variance is betweenand(Round all answers to 3 decimal places)

We are given, s2=14.6c=0.90n=22 The formula and calculations for the degree of freedom is as…

Answered: Confidence Level c = 0.90 and Sample…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Sample data from a normal population are located in the Microsoft Excel Online file below. Use the data to answer the following questions for the σ unknown case. Sample Data 1 4 11 2 10 17 5 11 Confidence Coefficient=0.95 The point estimate of the population mean is (to 2 decimals) The standard deviation is (to 2 decimals) The margin of error is (to 1 decimal) The 95% confidence interval is (to 1 decimal)
Independent random samples were selected from two quantitative populations, with sample sizes, means, and variances given below. Population 2 Sample Size 121 121 Sample Mean 3.2 5.7 Sample Variance 9.88 12.53 Construct a 90% confidence interval for estimating the difference in the population means (u, - H,). (Round your answers to two decimal places.) 3.2 X to 5.7 Construct a 99% confidence interval for estimating the difference in the population means. (Round your answers to two decimal places.) to
Do men have a higher body temperature than women? Test the indicated claim about the means of two populations. Assume that the two samples are randomly selected, independent, the population standard deviations are not know and not considered equal. The table shows results from a study of body temperatures of men and women. At the 0.05 significance level, test the claim that men have a higher body temperature than women. Men Women n1 = 13 n2 = 16 xˉx̄1 = 97 °F xˉx̄2 = 95.17 °F s1 = 0.26 °F s2 = 0.57 °F What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.)H0: Select an answer x̄₂ μ₁ p p₂ μ₂ μ μ(men) p̂₁ x̄₁ σ₁² p₁ s₁² ? > < ≥ ≠ ≤ = Select an answer p̂₁ p₁ μ μ₁ p x̄₁ μ₂ s₁² x̄₂ μ(women) σ₁² p₂ H1: Select an answer σ₂² μ p̂₂ p₁ p p₂ x̄₁ μ(men) x̄₂ μ₂ μ₁ s₂² ? = ≤ > < ≥ ≠ Select an answer s₁² x̄₁ μ₂ μ p̂₁ x̄₂ σ₁² μ(women) p₁ p p₂ μ₁ Original Claim = Select an answer H₀ H₁ df = Based on the hypotheses, find…
Analysis of Variance results: Where: Age > 5Responses: AgeFactors: Sex Response statistics by factor Sex n Mean Std. Dev. Std. Error female 121 10.490083 4.2222704 0.38384277 male 155 9.0806452 3.0091656 0.241702 ANOVA table Source DF SS MS F-Stat P-value Sex 1 134.98939 134.98939 10.466692 0.0014 Error 274 3533.79 12.897044 Total 275 3668.7794 Tukey HSD results (95% level) female subtracted from Difference Lower Upper P-value male -1.4094375 -2.2670907 -0.55178425 0.0014 In one complete sentence, interpret your confidence interval. Make sure in the interpretation it is clear the direction of the difference (i.e. which gender weighs more and by how much. Explain why a confidence interval provides more information to a tiger researcher than the results of a hypothesis test
To construct a 95% confidence interval of variance using a sample of 18 the critical values used are __________ and _____________.
3/12
Test the Variances.Assume both populations are normally distributed Họ: o Ho:0 = o HA:0 + 0 (Claim) %3D n1 = 6 , n2 = 14 a = 0.10 Two Sample F-Test for Variance Degrees of Freedom (Denominator) F-Test Statistic Degrees of Freedom (Numerator) dfN=n-1 F = Where sf> s Round all values to 3 decimal places a. The Critical Value FoD b. The Test Statistic F
onsider the following results for two independent random samples taken from two populations. Sample 1 Sample 2 n 1 = 50 n 2 = 30 x 1 = 13.1 x 2 = 11.2 σ 1 = 2.3 σ 2 = 3 What is the point estimate of the difference between the two population means? (to 1 decimal) Provide a 90% confidence interval for the difference between the two population means (to 2 decimals). Use z-table.( , ) Provide a 95% confidence interval for the difference between the two population means (to 2 decimals). Use z-table. If your answer is negative, enter minus (-) sign.( , )
WALKING RUNNING Mean 7.181818182 7.3636364 Variance 4.563636364 6.4545455 Observations 11 11 Pooled Variance 5.509090909 Hypothesized Mean Difference 0 df 20 t Stat -0.181668105 P(T<=t) one-tail 0.428835886 t Critical one-tail 1.724718243 P(T<=t) two-tail 0.857671772 t Critical two-tail 2.085963447 If the t-Stat value is less than the t Critical two-tail value I can reject the null, right? I am still a little confused on what a few numbers represent.

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Confidence Level c = 0.90 and Sample Size n = 22 %3D %3D Left Right 1+ Level of Significance a Degrees of Freedom 1 Confidence Interval for Variance o (n- 1)s² (n – 1)s² XR XL