Conduct the stated hypothesis test for μ ₁ μ2. Assume that the samples areindependent and randomly selected from normal populations.Ho : μι – μ2 = 01n₁ = 37n₂ = 31Standard Normal Distribution Tablea. Calculate the test statistic.0.00Z=Round to two decimal places if necessaryH₁Η : μι – μ2 70X 1 = 2,262X 2 = 2, 301= 0.0201 = 153.202 = 179.8α b. Determine the critical value(s) for the hypothesis test.Round to two decimal places if necessaryc. Conclude whether to reject the null hypothesis or not based on the test statistic.RejectFail to Reject

The null hypothesis is .The alternative hypothesis is The details of independent and randomly…

Answered: Conduct the stated hypothesis test for…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Calculate the standardized test statistic and the p-value
A A Aa Po APA- ability: Investigate F EBAL es/standard-normal-table 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 1.1 1.2 ve 1.3 1.4 344 F 8 temperature measurements are made in a laboratory over a period of time and the following values are obtained: 1.5 46,45,45,47,48,49,50,52 Use Chauvenet's criterion to identify any outliers in the data which should be rejected. Don't use the chauvenets table. Use the normal distribution table. ST 1.6 1.6 3.7 1.8 Z 0.00 0.01 0.02 0.03 0.04 0.0000 0.0040 0.0080 0.0120 0.0160 0.01990.025 0.07 0.08 0.09 0.0398 0.0438 0.0478 0.0517 0.0557 0.329 0.0832 0.0871 0.0910 0.0948 0.2549 Davos 0.3413 0.3438 0.3389 0.4015 0.4115 GAME 0.4265 0.4342 04304 0.4342 0.4394 0.4452 0.0398 0.0239 0.0279 0.0319 0.0359 0.0987 0.1036 0.0675 0.0714 0.0753 0.1179 0.1217 0.1255 0.1293 0.1331 0.1368 0.1406 0.1443 0.1480 0.1347 0.1064 0.1554 0.1591 0.1915 0.1950 0.125 0.1664 0.1700 0.1736 0.1772 0.1808 0.1846 0.1517 0.2257 0.2291 0.1985 0.2019 0.2054 0.2088 0.2123 0.2157…
5
A population of values has a normal distribution with μ=47.3μ=47.3 and σ=44.4σ=44.4. You intend to draw a random sample of size n=213n=213.Find the probability that a single randomly selected value is greater than 54.9.P(X > 54.9) = Find the probability that a sample of size n=213n=213 is randomly selected with a mean greater than 54.9.P(M > 54.9) = Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
According to a researcher, the average level of mercury uptake in wading birds in Everglades has declined over the past several years. Ten years ago, the average level was 15 parts per million (ppm). Suppose we are interested in testing whether the average level today is less than 15 ppm. Describe the type I error for the test of hypothesis. O The mean mercury level is equal to 15 ppm when in fact the mean is less than 15 ppm. O The mean mercury level is less than 15 ppm when in fact the mean is equal to 15 ppm. O The mean mercury level is greater than 15 ppm when in fact the mean is equal to 15 ppm.
Tests the claim that u1 < µ2. Assume the samples are random and independent. 01 = 0.78 ; ơ2 = 0.78 T = 34.7; 2 = 35.16 %3D = 31 ; n2 = 37 n1 = a. Calculate the Standard Error oz- = (3 decimal places) (2 decimal b. Calculate the Z-test statistic using the standard error from part a. : = places) C. At a = 0.01 , Use the distribution table to find the critical values for the rejection region (3 decimal places) = d. What is your conclusion? O Reject the alternative hypothesis and support the claim O Accept the alternative hypothesis and reject the claim O Fail to reject the null hypothesis and do not support the claim O Accept the null hypothesis and support the claim O Reject the null hypothesis and support the claim
A population of values has a normal distribution with μ=61.3μ=61.3 and σ=92.3σ=92.3. You intend to draw a random sample of size n=199n=199.Find the probability that a sample of size n=199n=199 is randomly selected with a mean between 49.5 and 80.9.P(49.5 < M < 80.9) =
Recreational Time A researcher wishes to see if there is a difference between the mean number of hours per week that a family with no children participates in recreational activities and a family with children participates in recreational activities. She selects two random samples and the data are shown. Use μ1 for the mean number of families with no children. At =α0.10, is there a difference between the means? Use the critical value method and tables. State the hypotheses and identify the claim. H0: Is a claim or not a claim H1: is a claim or not a claim One-tailed or two-tailed test? Find the critical value(s): Round the answer to at least 3 decimal places. Compute the test value: Round the answer to at least 3 decimal places. make the decision to reject or not to reject the null hypothesis. Summarize the results.There is enough evidence or not enough evidence to support the claim. X σ n No children 8.5 2.9 36 Children 10.5 2.7 36
A population of values has a normal distribution with μ=131.5μ=131.5 and σ=28.9σ=28.9. You intend to draw a random sample of size n=25n=25.Find the probability that a single randomly selected value is greater than 117.1.P(X > 117.1) = Find the probability that a sample of size n=25n=25 is randomly selected with a mean greater than 117.1.P(M > 117.1) = Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. Please can you break done step by step please. I ask a similar problem like this before and the answers fpr the homework were different. Thank you
Do one of the following, as appropriate: (a) Find the critical value za/2, (b) find the critical value ta/2, (c) state that neither the normal nor the t distribution applies. 98%; n = 7; 0 = 27; population appears to be normally distributed. Seleccione una: O A. Za2 = 2.33 B. Za2 = 2.05 C. ta2 = 2.575 %3D D. ta2 = 1.96 O O
A one-sample t test of Ho: u= 125 against Ha: µ> 125 is carried out based on sample data from a Normal population. The SRS of size n and s = 12.6. What is the P-value of the test in this situation? 15 produced a mean of x = 132.8 A) P= 0.008 B) P> 0.02 C) 0.02
In a test of Ho:= 90 against Ha: µ> 90, the sample data yielded the test statistic z = 2.17. Find and interpret the p-valte for the test. E Click the icon to view a table of standard normal values The p-value isp= (Round to three decimal places as needed.)

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