Conditional entropy. Let A and B = (Bo, B₁,..., Bn) be a discrete random variable and vector, respectively. The conditional entropy of A with respect to B is defined as H(A | B) = E (E{-log f(A | B) | B}) where f(a | b) = P(A = a | B = b). Let X be an aperiodic Markov chain on a finite state space. Show that and that H(Xn+1 | X0, X₁. , Xn) = H(Xn+1 | Xn), .... H(Xn+1 | Xn) →→лi Σ Pij i j if X is aperiodic with a unique stationary distribution . log Pij as n →∞,
Conditional entropy. Let A and B = (Bo, B₁,..., Bn) be a discrete random variable and vector, respectively. The conditional entropy of A with respect to B is defined as H(A | B) = E (E{-log f(A | B) | B}) where f(a | b) = P(A = a | B = b). Let X be an aperiodic Markov chain on a finite state space. Show that and that H(Xn+1 | X0, X₁. , Xn) = H(Xn+1 | Xn), .... H(Xn+1 | Xn) →→лi Σ Pij i j if X is aperiodic with a unique stationary distribution . log Pij as n →∞,
A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
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![Conditional entropy. Let A and B = (Bo, B₁,..., Bn) be a discrete random variable and
vector, respectively. The conditional entropy of A with respect to B is defined as H(A | B) =
E(E{-log f(A | B) | B}) where f(a | b) = P(A = a | B = b). Let X be an aperiodic Markov chain
on a finite state space. Show that
H(Xn+1 | X0, X₁. , Xn) = H(Xn+1 | Xn),
and that
H(Xn+1 \ Xn) → - ΣπιΣ pi;
i
j
if X is aperiodic with a unique stationary distribution .
log Pij
as n →∞,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F419ef6db-92c8-437a-a89f-3cae2cc1b951%2F0d192dfe-2af8-4013-9f20-88addfc94cd7%2F3f5t06b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Conditional entropy. Let A and B = (Bo, B₁,..., Bn) be a discrete random variable and
vector, respectively. The conditional entropy of A with respect to B is defined as H(A | B) =
E(E{-log f(A | B) | B}) where f(a | b) = P(A = a | B = b). Let X be an aperiodic Markov chain
on a finite state space. Show that
H(Xn+1 | X0, X₁. , Xn) = H(Xn+1 | Xn),
and that
H(Xn+1 \ Xn) → - ΣπιΣ pi;
i
j
if X is aperiodic with a unique stationary distribution .
log Pij
as n →∞,
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