Condisder the balanced chemical equation shown. A table of molecular weights is given below. 2 SiF4 (g) + Na2CO3 (s) + H2O (l) → Na2SiF6 (s) + SiO2 (s) + CO2 (g) + 2 HF (g) • How many grams of Na2SiF6 can be produced by the reaction of 70.00 grams of SiF4 and an excess amount
Condisder the balanced chemical equation shown. A table of molecular weights is given below. 2 SiF4 (g) + Na2CO3 (s) + H2O (l) → Na2SiF6 (s) + SiO2 (s) + CO2 (g) + 2 HF (g) • How many grams of Na2SiF6 can be produced by the reaction of 70.00 grams of SiF4 and an excess amount
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Condisder the balanced chemical equation shown. A table of molecular weights is given below.
2 SiF4 (g) + Na2CO3 (s) + H2O (l) → Na2SiF6 (s) + SiO2 (s) + CO2 (g) + 2 HF (g)
• How many grams of Na2SiF6 can be produced by the reaction of 70.00 grams of SiF4 and an excess amount of all other reactants?
Answer in grams of Na2SiF6
Molecular Weights
SiF4 104.077 g/mol
Na2CO3 105.988 g/mol
H2O 18.015 g/mol
Na2SiF6 188.053 g/mol
SiO2 60.083 g/mol
CO2 44.009 g/mol
HF 20.006 g/mol
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