concentration of the ethanol? M

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question:**

99.00 mL of a concentrated ethanol solution is added to a container to make 1.63 L of a 0.48 M diluted solution. What was the initial concentration of the ethanol?

**Answer Field:**

[          ] M

**Explanation:**

To solve this problem, use the dilution formula:

\[ C_1V_1 = C_2V_2 \]

Where:
- \( C_1 \) is the initial concentration of the ethanol (unknown in this case).
- \( V_1 \) is the initial volume of the ethanol solution (99.00 mL or 0.099 L).
- \( C_2 \) is the concentration of the diluted solution (0.48 M).
- \( V_2 \) is the final volume of the diluted solution (1.63 L).

Rearrange the formula to solve for \( C_1 \):

\[ C_1 = \frac{C_2V_2}{V_1} \]

Substitute the values into the equation:

\[ C_1 = \frac{0.48 \times 1.63}{0.099} \]

Calculate \( C_1 \) to find the initial concentration.
Transcribed Image Text:**Question:** 99.00 mL of a concentrated ethanol solution is added to a container to make 1.63 L of a 0.48 M diluted solution. What was the initial concentration of the ethanol? **Answer Field:** [ ] M **Explanation:** To solve this problem, use the dilution formula: \[ C_1V_1 = C_2V_2 \] Where: - \( C_1 \) is the initial concentration of the ethanol (unknown in this case). - \( V_1 \) is the initial volume of the ethanol solution (99.00 mL or 0.099 L). - \( C_2 \) is the concentration of the diluted solution (0.48 M). - \( V_2 \) is the final volume of the diluted solution (1.63 L). Rearrange the formula to solve for \( C_1 \): \[ C_1 = \frac{C_2V_2}{V_1} \] Substitute the values into the equation: \[ C_1 = \frac{0.48 \times 1.63}{0.099} \] Calculate \( C_1 \) to find the initial concentration.
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