Fill in the memory spaces as you trace the code from the beginning of the code to linc 17. Duc to the limitation of eClass, an almost similar memory space as below is created for you to fill in.3 public class Q4_2 {public static void main(String[] args) {int [] varl = {1, 2};int var2 = func_e(-100);int [] var3 - var1;var2 = func_1(var1, var3);45.9static int func_e (int x) {int [] y = new int [100];y[e] = x + 1ee;return y[0];101213static int func_1 (int [] x, int [] y) {int [] t = {x[e], y[i]};// here(151617181920 }return t[0]+t[1];Program Stack100Heap (GCH)

public class Q4_1{ public static coid main(string[ ] args){ int [ ] var1={1,2}; int var2=0;…

Answered: Fill in the memory spaces as you trace…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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"0->1(4),0->7(8),1->2(8),1->7(11),2->3(70)," In java I want a string with the numbers of single digit do not include the one inside the () and the number inside the () store in a array
OOPS ANS.
int a[100], b[1000], c[1000]; // get some data for a, b, and c for (i = 0; i < 100; i++) for (j = 0; j < 10; j++) a[i] += c[j*100 + i] * b[j*100 + i] ;
Write a OOP C++ Program You are required to create a class named List with given functionalities using pointers.class List{int arr[50];public:List();void add(int a);void remove(int a);void removeAt(int key);void addAt(int a, int index);void search(int a);void addAtStart(int a);void addAtLast(int a);}; Note: Don't copy paste write it your own.
int x=5; The variable is defined in c++ Array of Object O x=5 O Intx=5; x=8 is defined in c++ obs[4]=1; MyClass obs[4]=new Objec obs[4]; MyClass obs[4];
Please help with the JAVA code
The standard library function calloc(n,size) returns a pointer to n objects of size size, with the storage initialized to zero. Write calloc, by calling malloc or by modifying it.
5. Consider the following high-level code snippet. Assume that the base addresses of array1 and array2 are held in R1 and R2 and that array2 is initialized before it is used. int i; int array1 [100]; int array2 [100]; ... for (i=0; i<100; i=i+1) arrayl [i] = array2[i]; Write the code snippet in ARM assembly.
void func(vector<string>& names){ sort(names.begin(), names.end()); //(a) for(int i = names.size() - 1; i > 0; --i){. //(b) if(names[i] == names[i - 1]){ names[i] = move(names.back()); names.pop_back(); } } } What are the reasons or consequences for the programmer’s choice to loop backwards in the line marked (b), and under what circumstances would the algorithm behave differently if that line were replaced with: for (int i = 1; i < names.size(); ++i) ? What would change?
f18 In c++
1. Trace the execution of the following: {0, 1, 2, 3, 4, 5, 6, 7}; int[] anArray for (int i = 3; i 3; i--) 1]; What are the contents of anArray after the execution of each loop?
I'm creating a maze class using pointers and recursion and having some trouble setting up my number of Position functions. Maze.h: #ifndef MAZE_H #define MAZE_H /* * The allowed directions of travel within the Maze. */ enum direction {west, north, south, east}; /* * Represents a location within the Maze. */ struct coordinates { int x; int y; }; class Maze { public: Maze(); /* * It allows you to pick a seed for the pseudo-random number * generator and a size. A small size makes it easier for you * to see what your program is doing. Every instance with the same * seed and size is guaranteed to have the same Maze. */ Maze(int seed, int size); Maze(const Maze &); Maze&operator=(const Maze); ~Maze(); /* * numberOfPositions() returns a count which will hold the length * of the maximum possible path through the Maze. It's useful for * allocating enough characters to contain the successful path * through the Maze. */ int numberOfPositions(); /* * startingPosition() provides the caller…

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