# Java Program Q1b: Adding Positive Integers ## Task Description Complete the program `Q1b` that reads a set of integer values into the integer array `numbers` (this part is already done for you). Your task is to add up the positive values in the `numbers` array until the program encounters the value `999`. The number `999` is not included in the sum. At that point, the program should print the sum of the positive numbers and their average. ### Example 1 When the input is: `java Q1b 5 -3 8 999 7 1` - The program outputs: - Sum: `13` - Average: `6.5` ### Example 2 When the input is: `java Q1b 5 -3 8 7 1` - The program outputs: - Sum: `21` - Average: `5.25` ## Java Class Code ```java public class Q1b { public static void main (String[] args) { int[] numbers = new int[args.length]; for (int i = 0; i < args.length; i++) { numbers[i] = Integer.parseInt(args[i]); } // WRITE YOUR CODE HERE } } ``` ### Instructions - Initiate a loop through the `numbers` array. - Check each element; if it's positive, add it to a running total. - Stop processing when you encounter the number `999`. - Calculate and output the sum and average of the positive numbers encountered before `999`. This task helps reinforce the implementation of basic loops, conditional statements, and arithmetic calculations in Java. ```java public class Q1a { public static void main (String[] args) { int n = 1000; int mySum = 0; for (int i = n; i >= 0; i--) { if (i % 2 == 0) { mySum += i; } } StdOut.println(mySum); } } ``` **Explanation:** This Java program calculates the sum of all even numbers from 1000 down to 0. The program is structured as follows: 1. **Initialization:** - `int n = 1000;`: This variable `n` is set to 1000, representing the starting number. - `int mySum = 0;`: This variable `mySum` is initialized to 0 and will store the cumulative sum of even numbers. 2. **For Loop:** - `for (int i = n; i >= 0; i--)`: This loop iterates from `n` (1000) down to 0, decrementing `i` by 1 in each iteration. 3. **Condition Check:** - `if (i % 2 == 0)`: Inside the loop, an `if` statement checks if `i` is even. This is done by checking if the remainder when `i` is divided by 2 is zero. 4. **Summing Evens:** - `mySum += i;`: If `i` is even, it is added to `mySum`. 5. **Output:** - `StdOut.println(mySum);`: After the loop completes, the total sum of all even numbers from 1000 to 0 is printed. This program demonstrates basic looping and conditional logic in Java.