Compute the two regression equations on the basis of the following information : Y Mean 40 45 Standard deviation 10 Karl Pearson's correlation coefficient between X and Y = 0.50 the vaiue of Y for X Also estimate = 48 using the appropriate regression cquation.
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- For the following exercises, use Table 4 which shows the percent of unemployed persons 25 years or older who are college graduates in a particular city, by year. Based on the set of data given in Table 5, calculate the regression line using a calculator or other technology tool, and determine the correlation coefficient. Round to three decimal places of accuracyRespiratory Rate Researchers have found that the 95 th percentile the value at which 95% of the data are at or below for respiratory rates in breath per minute during the first 3 years of infancy are given by y=101.82411-0.0125995x+0.00013401x2 for awake infants and y=101.72858-0.0139928x+0.00017646x2 for sleeping infants, where x is the age in months. Source: Pediatrics. a. What is the domain for each function? b. For each respiratory rate, is the rate decreasing or increasing over the first 3 years of life? Hint: Is the graph of the quadratic in the exponent opening upward or downward? Where is the vertex? c. Verify your answer to part b using a graphing calculator. d. For a 1- year-old infant in the 95 th percentile, how much higher is the walking respiratory rate then the sleeping respiratory rate? e. f.Find the equation of the regression line for the following data set. x 1 2 3 y 0 3 4
- A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y).The results of the regression were:y=ax+b a=-1.38 b=39.555 r2=0.693889 r=-0.833 Assume the correlation is significant, and use this to predict the number of situps a person who watches 7 hours of TV can do (to one decimal place)A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y). The results of the regression were: y=ax+b a=-0.759 b=37.685 r2=0.674041 r=-0.821 Assume the correlation is significant, and use this to predict the number of situps a person who watches 11 hours of TV can do (to one decimal place)A researcher estimates a regression to test the effect of educational attainment (X;) on the average earnings of individuals (Y). The sample correlation coefficient (r) between years of educational attainment and the average earnings of individuals from a samp of 115 individuals was calculated to be 0.29. The value of the regression R will be (Round your answer to two decimal places.) The value of R indicates that the regressor (years of educational attainment) is at predicting the regressand (avera earnings of individuals). good not very good Enter your answer in the answer box. W DOLL e here to search
- 10) A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y).The results of the regression were:y=ax+b a=-0.767 b=31.009 r2=0.609961 r=-0.781 Use this to predict the number of situps a person who watches 7.5 hours of TV can do (to one decimal place)2. The instructor of a mathematics class collected data to see whether there is a correlation between the number of absences (X) and the student's score on the final exam (Y). The number of absences and score on the final exam were recorded. The following regression equation was obtained: Final score = 92.5317 – 3.7611 (Absences) a) (5 points) What would be the predicted final exam score for a student that had 10 absences? b) (5 points) The student from part (a) actually scored a 60 on the final exam. What is the residual for this student? Show all work.Find the simple regression line y=α+βx for the pairs of points belonging to the independent and dependent variables (xi,yi) , respectively. Also, interpret the result by calculating the Pearson correlation coefficient. Please dont use excel
- The following estimated regression equation based on 10 observations was presented. ŷ = = 26.1270 +0.5906x₁ +0.4980x2 (a) Develop a point estimate of the mean value of у when X1 = 170 and X₂ = 320. (b) Develop a point estimate for an individual value of y when X₁ = 170 and X₂ = 320.A statistics student wanted to determine if the distance to a destination was related to the price an airline would charge to fly to that destination. The student did a regression of airfare, y, on distance, x, and obtained the printout shown below from a statistical software package. Predictor Coef Constant 83.02 Distance 0.117 Oŷ= 0.117+83.02x Oy=83.02 +0.117x Oy= 49.29 + 83.02x Oŷ= 0.028 + 0.117x Oy=83.02 + 25.25x 1 SE Coef 49.29 0.028 S = 25.25 R-Sq = 63.2 % Which of the following is the correct equation of the least-squares line? Mark this and return t-ratio 1.689 4.179 R-Sq (Adj) = 64.7% Save and Exit р 0.046 0.000 di I tv Next AM Submit AaConsider a linear regression model for the decrease in blood pressure (mmHg) over a four-week period with muy=2.8+0.8x and standard deviation chi=3.2. The explanatory variable x is the number of servings fruits and vegetables in a calorie-controlled diet. The decrease in blood pressure y will vary about this subpopulation mean. What is the distribution of y for this subpopulation?