VASSESSMENT PROBLEMSObjective 1-Understand ac power concepts, their relationships to one another, and how to calcuate them in a circuit(A to B),Q = -866.03 VAR (B to A);10.1 For each of the following sets of voltage andcurrent, calculate the real and reactive powerin the line between networks A and B in thecircuit shown. In each case, state whether thepower flow is from A to B or vice versa. Alsostate whether magnetizing vars are being trans-ferred from A to B or vice versa.Answer: (a) P = 500 W(b) P = -866.03 WQ = 500 VAR(B to A),(A to B);(c) P = 500 WQ = 866.03 VAR (A to B);(A to B),a) v = 100 cos (wt – 45°) V;i = 20 cos (wt + 15°) A.(d) P = -500 WQ = -866.03 VAR (B to A).(B to A),- 45') V;b) v = 100 cos (wti = 20 cos (wt + 165') A.10.2 Compute the power factor and the reactive fac-c) v = 100 cos (wt -i = 20 cos (wt –45") V;105') A.tor for the network inside the box in Fig. 10.6,whose voltage and current are described inExample 10.1.d) v = 100 cos wt V;i = 20 cos (wt + 120°) A.Hint: Use -i to calculate the power and reac-tive factors.AВAnswer: pf = 0.5 leading; rf = -0.866.%3DNOTE: Also try Chapter Problem 10.1.

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Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

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VASSESSMENT PROBLEMS
Objective 1-Understand ac power concepts, their relationships to one another, and how to calcuate them in a circuit
(A to B),
Q = -866.03 VAR (B to A);
10.1 For each of the following sets of voltage and
current, calculate the real and reactive power
in the line between networks A and B in the
circuit shown. In each case, state whether the
power flow is from A to B or vice versa. Also
state whether magnetizing vars are being trans-
ferred from A to B or vice versa.
Answer: (a) P = 500 W
(b) P = -866.03 W
Q = 500 VAR
(B to A),
(A to B);
(c) P = 500 W
Q = 866.03 VAR (A to B);
(A to B),
a) v = 100 cos (wt – 45°) V;
i = 20 cos (wt + 15°) A.
(d) P = -500 W
Q = -866.03 VAR (B to A).
(B to A),
- 45') V;
b) v = 100 cos (wt
i = 20 cos (wt + 165') A.
10.2 Compute the power factor and the reactive fac-
c) v = 100 cos (wt -
i = 20 cos (wt –
45") V;
105') A.
tor for the network inside the box in Fig. 10.6,
whose voltage and current are described in
Example 10.1.
d) v = 100 cos wt V;
i = 20 cos (wt + 120°) A.
Hint: Use -i to calculate the power and reac-
tive factors.
A
В
Answer: pf = 0.5 leading; rf = -0.866.
%3D
NOTE: Also try Chapter Problem 10.1.

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Compute the power factor and the reactive factor
for the network inside the box in Fig. 10.6,
whose voltage and current are described in
Example 10.1.
Hint: Use -i to calculate the power and reactive
factors

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