compute the number of sequences formed from 3 a's, 5 b's, and 8 c's. a) that have no consecutive b's b) that have no consecutive symbols the same

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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compute the number of sequences formed from 3 a's, 5 b's, and 8 c's.

a) that have no consecutive b's

b) that have no consecutive symbols the same

 

The textbook solution is a) C(12,5)11!/(8!3!)      b) 2C(8,3)+14C(6,4)

I think I understand how to get a, I am just a bit confused on where the 11!/(8!3!)) comes from exactly. I am super lost on b. Thanks!

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