How many different 6-character license plates are possible if the first 4 places are to be occupied by numbers and the final 2 by letters? Repetition is possible and numbers may have leading zeroes. (a) 26! 10! * 4 * 2 (b) 264*10² (c) (26) (¹2) (d) 26² * 104 (e) None of the above

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A: Given::  1.2.3.4.5.6

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Q: How come the answer is actually 6188 combinations for (a) and 4186 combinations for (b)?

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A: Solution:

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A:

Q: 1 How many Os are in the product of 4 x 100? 4 X 1,000? 4 x 10,000? How do you know

A: We have to find out zeros