) compute the grade of the forward tangent. [Format: AX:XX%) A - sign [+ or -], X - numerical value b) compute the stationing of the highest point of the curve from the P.C. [Format: 0+000.00] c) compute the elevation of the highest point of the curve **USE 2 DECIMAL PLACES**

Q: Compute the passing sight distance available given a 435-ft curve, grades of g₁=+2.00% and 92 =…

A: Curve length, L = 435 fth1 = 3.25 fth2 = 4.50 ftg1 = 2 %g2 = -1.5 %VPI at station 96+80Elevation =…

Q: The preliminary design of a vertical curve shows the following e G1=-4.2%, G2=+1.6%, Station PVI=…

A:

Q: answer all parts

A:

Q: INSTRUCTIONS: Write your complete solutions with illustrations. 1. A compound curve is laid out 480…

A: The given data is shown below: Lc1=480mR1=763.94mLc2=250mR2=208.85mPI=10+432.25

Q: Degree of the curve as per chord definition is preferred for railways. True or False

A: It is asked to answer whether the given statement is true or false.

Q: surveying

A: Given I=30020'(a)Length =PT-PC=(1450.4)-(1260.5)=190Length=L=πRI180190=π(R)(30°20')180R=358.885Given…

Q: ermine the length L of the vertical curve mel the length of the vertical curve L on the sketch…

A: Summit curve BVC = Beginning of vertical curve EVC = End of vertical curve PVI =Intersection of…

Q: A-2.5% grade meets a +2.50% grade at station 4 + 200 and elevation 162.657 m, 180-m curve, stakeout…

A:

Q: For the PI Inaccessible problem: Sta. X = 70+00.00, XY =800.00 ft, angle x = 35°00'00", angle y =…

A: Sta. X = 70+00.00XY = 800.00 ftAngle X = 35Angle Y = 30The radius for the simple curve = 1000 ftTo…

Q: 2.50% grade meets a +1.75% grade at station 44+25 and elevation 3385.74 ft, 400-ft curve, stakeout…

A: The elevations and grades at the beginning and end of the curve need to be determined. We will call…

Q: För ån equal tangent vertical curve g1 = -4%, g2 = +3%, L = 300.00 ft, BVC Station = 10+00.00, BVC…

A:

Q: A horizontal curve is being designed around a pond with a tangent length of 800 ft and central angle…

A: Horizontal curve Horizontal curves are one of two key transition components in roadway geometric…

Q: For a highway curve with Da = 5°00', I = 20°30', and Pl station = 63 +25.53 ft, calculate the…

A: Given dataDegree of curve Da = 5°00'Intersection angle I = 20°30'PI station = 63+25.53 ft

Q: Highway curve has R = 1000 ft, I = 25°00', and Pl station = 26 + 40.00 ft.

A:

Q: Draw the shear diagram for the beam. Follow the sign convention. (Figure 1) Click on "add vertical…

A:

Q: Horizontal highway curve: Given PI at 95 + 54.78, Δ = 24°28’, and D = 5°30’, compute the deflections…

A:

Q: For the PI Inaccessible problem: Sta. X = 75+50.00, XY =800.00 ft, angle x = 35°00'00", angle y…

A: Given; Sta. X = 75+50.00 XY = 800.00 ft. angle X = 35 DEGREE angle Y = 30 DEGREE Radius for the…

Q: 24.14 Railroad curve with T 300.00 ft, D. 230', and PI station 48+ 00.00 24.13 Highway curve with T=…

A: Dc=2o30''   T=300 ft,  PI=48+00.00R=5729.6Dc=527362.5=2291.84 ftR=2291.84 ftTangent…

Q: Given G₁ & in decimals and a & L in feet, which of the following equations for the elevation of the…

A:

Q: Highway curve has R = 1000 ft, I = 25°00', and Pl station = 26 + 40.00 ft. Part A Determine degree…

A: R = 1000 ft I = 25o00'We have to find-(A) Determine degree of curvature Da of the curve.(B)…

Q: For a highway curve with D₁ = 5°00', I = 20°30', and Pl station = 63+ 25.53 ft, calculate the…

A: Step 1:Step 2:Step 3:Step 4:Step 5:Step 6:

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