Compute for the following and show the tabulated solutions: Azimuth (S) LINES AB Length 1,020.87 m 168°35' BC 1,117.26 m 263°30' CD 660.08 m 304°25' DE 495.85 m 5°30' EF 850.62 m 46°15' FA 855.45 m 112°30' a. Using Transit Rule, solve for adjusted latitudes, departures, distances, and bearings for all the traverse lines b. Using coordinate method and using the result of balancing traverse (transit rule) with station A (N,E) coordinates = (25 000, 27 500), solve for the coordinates (N,

Compute for the following and show the tabulated solutions: Azimuth (S) LINES AB Length 1,020.87 m 168°35' BC 1,117.26 m 263°30' CD 660.08 m 304°25' DE 495.85 m 5°30' EF 850.62 m 46°15' FA 855.45 m 112°30' a. Using Transit Rule, solve for adjusted latitudes, departures, distances, and bearings for all the traverse lines b. Using coordinate method and using the result of balancing traverse (transit rule) with station A (N,E) coordinates = (25 000, 27 500), solve for the coordinates (N,

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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10. TRANSIT RULE. Given in the accompanying tabulations are observed and calculated data for two different traverses. LATITUDE DEPARTURE AZIMUTH FROM SOUTH LINE DISTANCE +N -S +E 99°45' 154 00' 242 30' 353 15' AB 357.20 m 60.49 352.04 183. 18 164.64 80.30 CD 430.05 198.57 381.46 DA 425.18 422.23 49.97 Sums 1395.61m + 423. 70 -422.23 +431.43 -432,34 (D) (ENL) (ESL) (EED) (E WD)
Q1) The following sketch include inverting readings of some stations. Calculate the elevations of all stations. A Slope 6% C 3200 20 m 1.055 1.330 300 100 00m. BM
What is the correction for the latitude of BC using the transit method? Line AB BC CA a. 183.987 b. 185.879 c. 183.789 O d. 184.78 Length (m) 125.91 198.57 229.88 Consecutive co-ordinates Latitude -264.97 +182.96 +79.62 Departure +50.65 -104.62 +59.77
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Stadia Tacheometric Survey Problem 3. In the figure, the difference in elevation between observed points A and B is 15 m and the horizontal distance between them is 35 m. With transit at Station O, additional information was obtained as shown in the table. Determine the stadia intervals at A and B. Assume K=100 and C = 0. Occupied O Station Observed A B B RR (m) 1.863 1.500 S ? ? A VCR 12° 10⁰
Use compass rule. Express your answer in 4 decimal places. • Determine the adjusted angle of bearing of AB in degrees. • Determine the adjusted length of CD in meters. • Determine the adjusted length of AB in meters using transit rule.
fundamentals of surveying. transit rule.
Latitude and Departure Given the observed data of a closed traverse, determine the latitudes and departures of each line. Line Length Azimuth from North AB 161.460 m 228°20’ BC 180.490 m 267°43’ CD 171.830 m 352°01’ DE 229.700 m 82°12’ EA 130.550 m 131°48’ * Indicate the sign for latitude and departure * Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES. (Please provide a proven solution. Be mindful about the decimal places. Kindly answer this accurately. Thank You so much)
For the following observations 65.57, 65.39, 65.37, 65.48 m the line's most probable length is a) 65.45 b) 65.00 C) O 6.545 d) O 6545 Boş bırak
6. LATITUDES tabulations are the observed data pertaining to four diffe- rent traverses. CoOmpute and tabulate the latitudes and departures of each course. AND DEPARTURERS. Given in the accompanying AZIMUTH FROM SOUTH LINE LENGTH BEARING LINE DISTANCE NO0° 42'E S85 57'E so3* 04'w S52 51'w 242 30' 353 15' 99 45' 154 00 AB 732.72m JK 430.05 m BC 324.78 KL 425.18 CD 477.24 LM 357.20 DA 388.08 MJ 183.18 AZIMUTH COURSE LENGTH COURSE LENGTH BEARING FROM NORTH 228 20' 267 43' 352 01' 82 12' 131 48' N59 33'E S39 18'E so6*35'w NI7:48'w N70°59'w 1-2 161.46 m 1-2 427.00 m 301.95 180.49 2-3 3-4 2-3 171.83 3-4 445.66 4-5 229.70 326.73 434.50 4-5 5-1 130.55 5-1 7. ERROR OF CLOSURE. Given the following tabulated data for vevs