TRANSIT RULE. Given in the accompanying tabulations are observed and calculated data for two diff. traverses DEPARTURELATITUDEAZIMUYHFROM NORTHCOURSELENGTH- W+N--S+E5.530°50'296°06'205 54'135 20'33°27'95°39'380. 38 m51 9. 30CD380. 34466.35DE228.46624.18303.08EF693. 87FG41 7.98297.27293.83GH403.93337.03222.6524.51247.79HC249. 00Sums2664. 46 m+945.83-945.96+769.80-769.43ENL)ESL)ZEDI(EWD)(D)each set of traverse data,by the transit rule.Forbalance the latitudesandde parturesAlso determine the linearbearing of the side of error,theTabulate all observedcalculated values into a convenient for mat and preparea sketch of the adjusted traverse. Use a 'convenient scale.errorof closure,andprecision of the measurements made.and

Transit Rule: The transit rule is generally used in surveying for balancing the traverse. In other…

DEPARTURE LATITUDE AZIMUYH COURSE LENGTH FROM NORTH +N -S +E 5.53 0°50' 296°06' 205 54' 135 20' 33 27' 95°39' CD 380. 38 m 380. 34 466.35 DE 519.30 228.46 624.18 303.08 EF 693.87 FG 417.98 297.27 293.83 GH 403.93 337.03 222.65 HC 249. 00 24.51 247.79 Sums 2664.46 m +945.83 -945.96 +769.80 -769.43 {D) ENL) ESL) ZEDI (ZWO) each set of traverse data, balance the latitudes and For departures by the transit rule. error of closure, precision of the measurements made. and Also determine the linear the observed bearing of the side of error, Tabulate all and calculated values into a convenient format and prepare a sketch of the adjusted traverse. Use a 'convenient scale.

DEPARTURE LATITUDE AZIMUYH COURSE LENGTH FROM NORTH +N -S +E 5.53 0°50' 296°06' 205 54' 135 20' 33 27' 95°39' CD 380. 38 m 380. 34 466.35 DE 519.30 228.46 624.18 303.08 EF 693.87 FG 417.98 297.27 293.83 GH 403.93 337.03 222.65 HC 249. 00 24.51 247.79 Sums 2664.46 m +945.83 -945.96 +769.80 -769.43 {D) ENL) ESL) ZEDI (ZWO) each set of traverse data, balance the latitudes and For departures by the transit rule. error of closure, precision of the measurements made. and Also determine the linear the observed bearing of the side of error, Tabulate all and calculated values into a convenient format and prepare a sketch of the adjusted traverse. Use a 'convenient scale.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Given the following tabulated data for a closed traverse in which the lengths of BC and CD have not been measured in the field. Determine these unknown quantities. LATITUDES DEPARTURES LINE LENGTH BEARING N E W AB 639.32 m N 09° 30' W BC UNKNOWN N 56° 55' W CD UNKNOWN S 56° 13' W DE 570.53 S02° 02' E EA 1,082.71 S89° 31'E SUMS
A closed traverse has the following data: Line Bearing Distance (m) AB N 30deg 30min W 56.50 BC N 75deg 30min W 47.80 CD S 45deg 30min W 85.70 DA Find the area of the traverse.
For the given data of a close traverse, determine the missing distance of course CD and the bearing of course DE, solve the AREA using DPD. Sketch the traverse. *Inserted Photo*
2. Correct the survey data below for a closed traverse. LINE OBSERVED DIMENSIONS DISTANCE BEARING (m) АВ 319.27 N 86°46' E N 1°35' W S 78°50' ВС 551.35 CD 417.26 W DE 220.87 S 30°25' W EA 375.36 S 36°17' E
Triangulation stations A,B,C and D has the following observation angles. Angles: ACB=50° BAD=20° BCD=30° ABC=50° CAD=60° a. Find the angle CBD. b. Find the angle BDA. C. Find the angle BCD.
Compute the area of the traverse data shown.
A closed traverse has the following data in the table. Use transit rule in balancing the traverse. What is the linear error of closure? LINE LENGTH(m) BEARING АВ 430.05 N 62°30' E BC unknown S 6°45' E CD 357.20 unknown DA 183.18 N 26°00' W
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Problem 6 For the given data of a close traverse, determine the missing distance of course CD and the bearing of course EF. Solve the AREA using DMD and sketch the traverse. DISTANCE LINES BEARING LATITUDE DEPARTURE DMD DOUBLE AREA (m) AB 78 5 78°11' E BC 49 5 45°26' E CD 5 34°05' w DE 115 N 32°18' W EF 65 FA 62 N 29°20' w Area
A level loop was run and the raw elevations in Table 2 were calculated based on backsights and foresights. A plan view of the loop is shown in Figure 2. The true elevation of BM1 is 195.00 ft. Adjust the elevation of each station such that the error is evenly spaced. Show sample calculations of your work. Also determine the accuracy ratio of the survey. BM₁ 5 mi 3 mi BM2 BM4 3 mi BM3 4 mi Figure 2 Table 2 Station Raw Elevation [ft] BM1 195.0 BM2 205.6 BM3 209.8 BM4 204.7 BM1 195.5
I. TRANSIT RULE. Given in the accompanying tabulation are the observed data for a traverse obtained from a transit- tape survey. De- termine the latitudes and departures of each course and balance these quantities by employing the transit rule. Tabulate values accordingly. COURSE LENGTH AB BC CD 495.85m 850.62 855.45 AZIMUTH FROM NORTH 5°30' 46 02' 112°22' COURSE LENGTH 1,020.87m 1,117.26 660.08 DE EF FA AZIMUTH FROM NORTH 167°35' 263 44' 304°51' 2. ADJUSTMENT OF LENGTHS AND AZIMUTHS. Given the observed and calculated data in Problem No. I. Determine the adjusted length and adjusted azimuth (reckoned from north) of each course and tabulate values accordingly.