(For Nos 15 to 18). The ke value for the equimolar counterdiffusion between A and B was determined to be 1.75 x 10-7 kgmol/s•m² · Pa. 15. Compute for the kg value for A diffusing through stagnant B at 298.15 K and Protal = 1 atm. Gas A has a partial pressure of 0.30 atm at the gas phase and 0 atm at the interface. a. 2.0806 x 10-7 kgmol/s m2 · Pa b. 6.3245 x 10-3 kgmol/s m² . Pa c. 0.02108 kgmol/s·m² · Pa d. 0.51577 kgmol/s m2 - Pa 16. Compute for the k, value for A diffusing through stagnant B. a. 2.0806 x 10-7 m/s b. 6.3245 x 10-3 m/s c. 0.02108 m/s d. 0.51577 m/s 17. Compute for the k, value for A diffusing through stagnant B. a. 2.0806 x 10-7 kgmol/s m² · mol frac
(For Nos 15 to 18). The ke value for the equimolar counterdiffusion between A and B was determined to be 1.75 x 10-7 kgmol/s•m² · Pa. 15. Compute for the kg value for A diffusing through stagnant B at 298.15 K and Protal = 1 atm. Gas A has a partial pressure of 0.30 atm at the gas phase and 0 atm at the interface. a. 2.0806 x 10-7 kgmol/s m2 · Pa b. 6.3245 x 10-3 kgmol/s m² . Pa c. 0.02108 kgmol/s·m² · Pa d. 0.51577 kgmol/s m2 - Pa 16. Compute for the k, value for A diffusing through stagnant B. a. 2.0806 x 10-7 m/s b. 6.3245 x 10-3 m/s c. 0.02108 m/s d. 0.51577 m/s 17. Compute for the k, value for A diffusing through stagnant B. a. 2.0806 x 10-7 kgmol/s m² · mol frac
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
Question
![(For Nos 15 to 18). The k value for the equimolar counterdiffusion between A and B was determined to be
1.75 x 10-7 kgmol/s m2 Pa.
15. Compute for the kg value for A diffusing through stagnant B at 298.15 K and Protal = 1 atm. Gas A has a partial
pressure of 0.30 atm at the gas phase and 0 atm at the interface.
a. 2.0806 x 10-7 kgmol/s m2 Pa
b. 6.3245 x 10-3 kgmol/s m² - Pa
c. 0.02108 kgmol/s m2 Pa
d. 0.51577 kgmol/s m? . Pa
16. Compute for the k, value for A diffusing through stagnant B.
a. 2.0806 x 10-7 m/s
b. 6.3245 x 10-3 m/s
c. 0.02108 m/s
d. 0.51577 m/s
17. Compute for the k, value for A diffusing through stagnant B.
a. 2.0806 x 10-7 kgmol/s m2 - mol frac
b. 6.3245 x 10-3 kgmol/s · m2 - mol frac
c. 0.02108 kgmol/s m2 mol frac
d. 0.51577 kgmol/s m2 mol frac
18. Compute for the flux, Na, under A diffusing through stagnant B (absolute value).
a. 2.0806 x 10-7 kgmol/s m?
b. 6.3245 x 10-3 kgmol/s m?
0.02108 kgmol/s m?
d. 0.51577 kgmol/s m2
C.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa7b67a2a-afd1-4f89-96e2-8f17c268311b%2F9059edcc-4db6-4f63-ad34-fcad4fe3cd72%2Fddwvhma_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(For Nos 15 to 18). The k value for the equimolar counterdiffusion between A and B was determined to be
1.75 x 10-7 kgmol/s m2 Pa.
15. Compute for the kg value for A diffusing through stagnant B at 298.15 K and Protal = 1 atm. Gas A has a partial
pressure of 0.30 atm at the gas phase and 0 atm at the interface.
a. 2.0806 x 10-7 kgmol/s m2 Pa
b. 6.3245 x 10-3 kgmol/s m² - Pa
c. 0.02108 kgmol/s m2 Pa
d. 0.51577 kgmol/s m? . Pa
16. Compute for the k, value for A diffusing through stagnant B.
a. 2.0806 x 10-7 m/s
b. 6.3245 x 10-3 m/s
c. 0.02108 m/s
d. 0.51577 m/s
17. Compute for the k, value for A diffusing through stagnant B.
a. 2.0806 x 10-7 kgmol/s m2 - mol frac
b. 6.3245 x 10-3 kgmol/s · m2 - mol frac
c. 0.02108 kgmol/s m2 mol frac
d. 0.51577 kgmol/s m2 mol frac
18. Compute for the flux, Na, under A diffusing through stagnant B (absolute value).
a. 2.0806 x 10-7 kgmol/s m?
b. 6.3245 x 10-3 kgmol/s m?
0.02108 kgmol/s m?
d. 0.51577 kgmol/s m2
C.
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Follow-up Question
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![18. Compute for the flux, Na, under A diffusing through stagnant B (absolute value).
a. 2.0806 x 10-7 kgmol/s m?
b. 6.3245 x 10-3 kgmol/s m?
c. 0.02108 kgmol/s m2
d. 0.51577 kgmol/s m2](https://content.bartleby.com/qna-images/question/a7b67a2a-afd1-4f89-96e2-8f17c268311b/cbd6ebc2-bd9f-44e5-868f-93864e7117ab/1x28k5q_thumbnail.jpeg)
Transcribed Image Text:18. Compute for the flux, Na, under A diffusing through stagnant B (absolute value).
a. 2.0806 x 10-7 kgmol/s m?
b. 6.3245 x 10-3 kgmol/s m?
c. 0.02108 kgmol/s m2
d. 0.51577 kgmol/s m2
Solution
Follow-up Question
![18. Compute for the flux, Na, under A diffusing through stagnant B (absolute value).
a. 2.0806 x 10-7 kgmol/s m?
b. 6.3245 x 10-3 kgmol/s m?
c. 0.02108 kgmol/s m2
d. 0.51577 kgmol/s m2](https://content.bartleby.com/qna-images/question/a7b67a2a-afd1-4f89-96e2-8f17c268311b/804e0b12-5761-48a5-9167-619635d20c74/tw0d9sp_thumbnail.jpeg)
Transcribed Image Text:18. Compute for the flux, Na, under A diffusing through stagnant B (absolute value).
a. 2.0806 x 10-7 kgmol/s m?
b. 6.3245 x 10-3 kgmol/s m?
c. 0.02108 kgmol/s m2
d. 0.51577 kgmol/s m2
Solution
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